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3 years ago

Cellular network towers are configured in such a way so that they avoid what type of problem?

Engineering

2 answers:

stiv31 [10]3 years ago

6 0

Avoiding OVERLAP issues

Elenna [48]3 years ago

3 0

Answer:

They are configured this way to avoid overlap issues.

Explanation:

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Flura [38]

Answer:

-2/√3 atan ((2t + 1)/√3) + C

Explanation:

∫ (t − 1) / (1 − t³) dt

Factor the difference of cubes:

∫ (t − 1) / ((1 − t)(1 + t + t²)) dt

Divide:

∫ -1 / (1 + t + t²) dt

-∫ 1 / (t² + t + 1) dt

Complete the square:

-∫ 1 / (t² + t + ¼ + ¾) dt

-∫ 4 / (4t² + 4t + 1 + 3) dt

-∫ 4 / ((2t + 1)² + 3) dt

If u = 2t + 1, du = 2 dt:

-∫ 2 / (u² + 3) du

Use an integral table, or use trigonometric substitution:

-2 (1/√3) atan (u/√3) + C

-2/√3 atan (u/√3) + C

Substitute back:

-2/√3 atan ((2t + 1)/√3) + C

4 0

3 years ago

Which statements describe how the Fed responds to high inflation? Check all that apply.

Sveta_85 [38]

Answer:
• it charges banks more interest
• it sells more securities
• it decreases the money supply

In response to high inflation, the Fed charges banks more interests and pays the banks less interests. It also sells not securities.

8 0

3 years ago

Consider a 8-m-long, 8-m-wide, and 2-m-high aboveground swimming pool that is filled with water to the rim. (a) Determine the hy

Stolb23 [73]

Answer:

The hydrostatic force of 313920 N is acted on each wall of the swimming pool and this force is acted at 1 m from the ground. The hydrostatic force is quadruple if the height of the walls is doubled.

Explanation:

To calculate force on the walls of swimming pool whose dimensions are given as 8-m-long, 8-m-wide, and 2-m-high. We know that formula for hydrostatic force is $\text {hydrostatic force}=\text {pressure} \times \text {area,}=\rho g h \times(l \times h)$

$\equiv \rho g h^{2} l$ , we know ρ=density of fluid=1000 $g / c m^{3}$ ,

g=acceleration due to gravity=9.81 $m / s^{2}$ , h=height of the pool=2 m and l=length of the pool=8 m.

hydrostatic force on each wall= $1000 \times 9.81 \times 2^{2} \times 8$ = 313920 N.

The distance at which hydrostatic force is acted is half of the height of the swimming pool.

At 1 m from the ground this hydrostatic force is acted on each wall.

The force is quadruple if the height of the walls of the pool is doubled this is because, the height is doubled and taken as h=4 m and substitute in the equation = $\rho g h^{2} l$ = $1000 \times 9.81 \times 4^{2} \times 8$ = 1255680 N. This is 4 times 313920 N.

5 0

3 years ago

A mercury thermometer has a cylindrical capillary tube with an internal diameter of 0.2 mm. If the volume of the thermometer and

vova2212 [387]

To solve this problem we will proceed to calculate the specific volume from the area of the cylinder and the sensitivity. Later we will calculate the volumetric coefficient of thermal expansion and finally we will be able to calculate the volume through the relation of the two terms mentioned above. Our values are

$\text{Sensitivity}= 2mm/\°C$

$\text{Internal diameter } d= 0.2mm$

$\text{Differential expansion of Hg } \lambda_L = 1.82*10^{-4}/\°C$

Let's start by calculating the specific volume which is given by

$v = \pi (\frac{d}{2})^2 \gamma$

Here,

d = Diameter

$\gamma$ = Sensitivity

Replacing our values we have

$v = (\frac{\pi}{4})(0.2mm)^2(2mm/\°C)$

$v = 0.0628mm^3 /\°C$

Now we will obtain the value of the volumetric coefficient of thermal expansion of mercury through the differential expansion coefficient of Hg whic is three times, then

$\lambda_V = 3\lambda_L$