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erastova [34]
2 years ago
12

A buffer is a solution that: Select one: a. Results from mixing a strong acid and a strong base. b. When added to another soluti

on, decreases the pH. c. When added to another solution, increases the pH. d. Prevents a drastic change in pH when an acid or base enters a solution.
Chemistry
1 answer:
Kruka [31]2 years ago
5 0

Answer:

d. Prevents a drastic change in pH when an acid or base enters a solution.

Explanation:

The purpose of a buffer is to resist pH change and keep the solution relatively stable.

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What happens when gases change to plasma?
IgorLugansk [536]

Answer:. In the case of neon, it is electrical energy that pulls the electrons off.

explanation-Plasma can be made from a gas if a lot of energy is pushed into the gas. In the case of neon, it is electrical energy that pulls the electrons off. When it is time to become a gas again, just flip the neon light switch off. Without the electricity to energize the atoms, the neon plasma returns to its gaseous state.

8 0
3 years ago
A compound X has the following percentage composition 66.7% carbon, 11.1% hydrogen and 22.2% oxygen .Calculate the empirical for
Digiron [165]

Explanation:

c. h. o

66.7%. 11.1%. 22.2%

____. ____. ____

12. 1. 16

1.558. 11.1. 1.39. (divide by the smallest)

1. 8. 1

empirical formula=ch8o

4 0
3 years ago
Hurry please!
Pani-rosa [81]

Answer : The mass of of water present in the jar is, 298.79 g

Solution : Given,

Mass of barium nitrate = 27 g

The solubility of barium nitrate at 20^oC is 9.02 gram per 100 ml of water.

As, 9.02 gram of barium nitrate present in 100 ml of water

So, 27 gram of barium nitrate present in \frac{27g}{9.02g}\times 100ml=299.33ml of water

The volume of water is 299.33 ml.

As we know that the density of water at 20^oC is 0.9982 g/ml

Now we have to calculate the mass of water.

\text{Mass of water}=\text{Density of water}\times \text{Volume of water}

\text{Mass of water}=(0.9982g/ml)\times (299.33ml)=298.79g

Therefore, the mass of of water present in the jar is, 298.79 g

5 0
2 years ago
The data below shows the change in concentration of dinitrogen pentoxide over time, at 330 K, according to the following process
tensa zangetsu [6.8K]

Answer: a) 1.7\times 10^{-4}

b) 3.4\times 10^{-4}

Explanation:

The reaction is :

2N_2O_5(g)\rightarrow 4NO_2(g)+O_2(g)

Rate = Rate of disappearance of N_2O_5 = Rate of appearance of NO_2

Rate =  -\frac{d[N_2O_5]}{2dt} = \frac{d[NO_2]}{4dt}

Rate of disappearance of N_2O_5 = \frac{\text {change in concentration}}{time} = \frac{0.100-0.066}{200-0}=1.7\times 10^{-4}

a) Rate of disappearance of N_2O_5 = -\frac{d[N_2O_5]}{2dt}

Rate of appearance of NO_2 = \frac{d[NO_2]}{4dt}

b) Rate of appearance of NO_2 =  \frac{d[NO_2]}{dt}=2\times 1.7\times 10^{-4}}=3.4\times 10^{-4}

8 0
2 years ago
How would one convert 6 pounds to ounces (16 oz = 1b)?
NNADVOKAT [17]

Answer:

D.

Explanation:

I just got it right in the test :)

6 0
3 years ago
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