Question

For #8 and #9, fill in the missing information for the following trapezoids. SHOW YOUR WORK to solve for the missing value.

Answer 1

Applying the equation for the area of the trapezoid, it is found that the height is of 10 cm.

The area of a trapezoid is half the multiplication of the sum of the bases and the height, that is:

$A = \frac{h}{2}(b_1 + b_2)$

For this problem, we have that: $A = 205, b_1 = 20, b_2 = 21$, hence:

$A = \frac{h}{2}(b_1 + b_2)$

$205 = \frac{h}{2}(20 + 21)$

$20.5h = 205$

$h = \frac{205}{20.5}$

$h = 10$

The height is of 10 cm.

To learn more about area of a trapezoid, brainly.com/question/9918120

Answer 2

Answer:

The height of trapezoid is 10 cm.

Step-by-step explanation:

Given :

• »» $\rm{b_1}$ = 20 cm
• »» $\rm{b_2}$ = 21 cm
• »» $\rm{area}$ = 205 cm²

To Find :

• »» Height of trapezoid

Using Formula :

${\star{\small{\underline{\boxed{\sf{\red{Area_{(Trapezoid)} = \dfrac{1}{2} \Big(b_1 + b_2\Big)h}}}}}}}$

• ✧ $\rm{b_1}$ = 20 cm
• ✧ $\rm{b_2}$ = 21 cm
• ✧ $\rm{area}$ = 205 cm²

Solution :

Substituting all the given values in the formula to find height of trapezoid :

${\dashrightarrow{\small{\sf{Area_{(Trapezoid)} = \dfrac{1}{2} \Big(b_1 + b_2\Big)h}}}}$

${\dashrightarrow{\small{\sf{205 = \dfrac{1}{2} \Big(20 + 21\Big)h}}}}$

${\dashrightarrow{\small{\sf{205 = \dfrac{1}{2} \Big( \: 41 \: \Big)h}}}}$

${\dashrightarrow{\small{\sf{205 = \dfrac{1}{2} \times 41 \times h}}}}$

${\dashrightarrow{\small{\sf{205 = \dfrac{ 41}{2}\times h}}}}$

${\dashrightarrow{\small{\sf{h = 205 \times \dfrac{2}{41}}}}}$

${\dashrightarrow{\small{\sf{h = \cancel{205} \times \dfrac{2}{\cancel{41}}}}}}$

${\dashrightarrow{\small{\sf{h =5 \times 2}}}}$

${\dashrightarrow{\small{\sf{h =10 \: cm}}}}$

${\star{\small{\underline{\boxed{\frak{\pink{h =10 \: cm}}}}}}}$

Hence, the height of trapezoid is 10 cm.

$\rule{300}{1.5}$