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4vir4ik [10]
3 years ago
7

If the wavelength of a sound wave increases and the frequency of the sound wave does not change what happens to the speed of the

wave?
a. it will stay the same

b. it will decrease

c. it cannot be determined

d. it will increase
Physics
1 answer:
salantis [7]3 years ago
3 0

If the wavelength of a sound wave increases and the frequency of the sound wave does not change, the speed of the wave will increase.

Ans: D

Explanation

The sound wave speed is given by E=fλ, where f indicates its frequency and λ indicates its wavelength.

From the equation, it is evident that the sound speed is proportional to both frequency and wavelength.

Here, as wavelength increases, wave speed increases provided there is no change in frequency.

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True or False: The average speed of an object is always equal to the magnitude of the average velocity of the object. If False,
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Q C Blaise Pascal duplicated Torricelli's barometer using a red Bordeaux wine, of density 984kg/ m³ , as the working liquid (Fig
levacccp [35]

The pressure within Earth's atmosphere is referred to as atmospheric pressure or barometric pressure. 10.701 was the height h of the wine column for normal atmospheric pressure.

<h3>What is Atmospheric pressure?</h3>

The pressure within Earth's atmosphere is referred to as atmospheric pressure or barometric pressure. The definition of the standard atmosphere is 101,325 Pa, or the same as 1013.25 millibars, 760 mm Hg, 29.9212 inches Hg, or 14.696 psi.

The force per unit area that an atmospheric column exerts is known as atmospheric pressure, often known as barometric pressure (that is, the entire body of air above the specified area). A weather indicator is atmospheric pressure. There will typically be clouds, wind, and precipitation when a low-pressure system enters a region. Fair, quiet weather is frequently a result of high pressure systems.

We have the density for the red Bordeaux wine given $\rho=965 \frac{\mathrm{kg}}{\mathrm{m}^3}$, the atmospheric pressure on the Torricelli's barometer is given by:

$$P_{a t m}=\rho g h$$

Solving for the height of wine in the column we have this:

$h=\frac{P_{\text {anm }}}{\rho g}$

And replacing we have:

h=\frac{101300 \mathrm{~Pa}}{965 \frac{\mathrm{kg}}{\mathrm{m}^3 9.81 \frac{\mathrm{m}}{\mathrm{m}^2}}}=10.701 \mathrm{~m}$$

So the height of the red Bordeaux wine would be $\mathrm{h}=10.701 \mathrm{~m}$. A very high value on this case if we compare with the usual values for this variable.

To learn more about Atmospheric pressure refer to:

brainly.com/question/19587559

#SPJ4

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