If the wavelength of a sound wave increases and the frequency of the sound wave does not change what happens to the speed of the
wave?
a. it will stay the same
b. it will decrease
c. it cannot be determined
d. it will increase
1 answer:
If the wavelength of a sound wave increases and the frequency of the sound wave does not change, the speed of the wave will increase.
Ans: D
Explanation
The sound wave speed is given by E=fλ, where f indicates its frequency and λ indicates its wavelength.
From the equation, it is evident that the sound speed is proportional to both frequency and wavelength.
Here, as wavelength increases, wave speed increases provided there is no change in frequency.
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Explanation:
p=w/t
t=w/p
t=225/25=9seconds
Answer:
B. The particles that make up material B have more mass than the
particles that make up material A.
Explanation:
C. insulator
Hope this helps ya!
Answer:

Explanation:
Given, for girl : Weight or force;

Area of both heels;


For elephant, Weight = Force
= 2000 kg•f
Area of 4 feet;


Now;



Thus, the girl's pointed heel sandals exert 12.5 times more pressure P than the pressure P exerted by the elephant.
I aspire this helps!
Answer:
2.71 m
Explanation:
Force is the product of mass and acceleration
F=m*a
Work done is the product of force and distance
Work done=F*d
In this case;
F= 35 N
Work done = 95 J
95 =35 * d
95 /35 = d
2.71 m= d