Lithium has charge of +1 and bromide has charge of - 1. So they combine to form the compound lithium bromide which is expressed as LiBr.
<h3><u>Explanation:</u></h3>
Lithium is an alkali metal placed in group 1 or periodic table. It has a valency of 1 which is achieved as lithium loses an electron to achieve a charge of +1.
Bromine is a halogen which is placed in group 17 of periodic table. It has a valency of 1 which is achieved as bromine looses an election to achieve a charge of - 1.
Lithium is the cation and bromide is the anion. So lithium is written in front and bromine following the cation. And as both of their valencies are 1, so they form the compound LiBr.
Answer:
0.03 L
Explanation:
Step 1: Given data
- Initial volume of the balloon (V₁): 0.5 L
- Initial temperature of the balloon (T₁): 293 K
- Final volume of the balloon (V₂): ?
- Final temperature of the balloon (T₂): 20 K
Step 2: Calculate the final volume of the balloon
The balloon is filled with air. If we assume it behaves as an ideal gas, we can calculate the final volume of the balloon using Charles' law.
V₁/T₁ = V₂/T₂
V₂ = V₁ × T₂/T₁
V₂ = 0.5 L × 20 K/293 K = 0.03 L
