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babymother [125]
2 years ago
5

I neeeed helppppp!!!!!!!

Chemistry
1 answer:
Nezavi [6.7K]2 years ago
7 0

Answer:

The first claim is false. Natural resources can most definitely exist without synthetic products.

Explanation:

All synthetic products are derived from natural resources as everything has to come from a source in the beginning. However, most natural resources themselves are the source, make sense? For example, water is a naturally occurring resource, but even water is derived from specific components, however it doesn't need anything synthetic to exist. Now take hairspray, to make hairspray you need water and synthetic resources, see where I'm going with that?

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How many grams of nitric acid HNO₃, are required to neutralize (completely react with) 4.30 grams of Ca(OH)2 according to the ac
Brrunno [24]

Answer:

7.32g of HNO3 are required.

Explanation:

1st) From the balanced reaction we know that 2 moles of HNO3 react with 1 mole of Ca(OH)2 to produce 2 moles of H2O and 1 mole of Ca(NO3)2.

From this, we find that the relation between HNO3 and Ca(OH)2 is that 2 moles of HNO3 react with 1 mole of Ca(OH)2.

2nd) This is the order of the relations that we have to use in the equation to calculate the grams of nitric acid:

• starting with the 4.30 grams of Ca(OH)2.

,

• using the molar mass of Ca(OH)2 (74g/mol).

,

• relation of the 2 moles of HNO3 that react with 1 mole of Ca(OH)2 .

,

• using the molar mass of HNO3 (63.02g/mol).

4.30g\text{ Ca\lparen OH\rparen}_2*\frac{1\text{ mol Ca\lparen OH\rparen}_2}{74g\text{ Ca\lparen OH\rparen}_2}*\frac{2\text{ moles HNO}_3}{1\text{ mole Ca\lparen OH\rparen}_2}*\frac{63.02g\text{ HNO}_3}{1\text{ mole HNO}_3}=7.32g\text{ HNO}_3

So, 7.32g of HNO3 are required.

4 0
1 year ago
CaC2(s) + 2H2O(l) --> Ca(OH)2(aq) + C2H2(g) In the reaction above, 0.5487 grams of calcium carbide are completely consumed to
jasenka [17]

Answer:

239.7mL

Explanation:

Using the general gas equation;

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas constant (0.0821 Latm/molK)

T = temperature (K)

The balanced chemical equation in this question is as follows:

CaC2(s) + 2H2O(l) --> Ca(OH)2(aq) + C2H2(g)

From the equation, 1 mole of CaC2 produces 1 mole of ethylene gas, C2H2.

Using mole = mass/molar mass

Molar mass of CaC2 = 40 + 12(2)

= 40 + 24

= 64g/mol

mole = 0.5487/64

mole = 0.00857mol of CaC2

Hence, 0.00857mol of CaC2 produced 0.00857mol of C2H2

Based on the information provided, n = 0.00857mol, T = 43°C = 43 + 273 = 316K, p = 0.926 atm

PV = nRT

V = nRT/P

V = 0.00857 × 0.0821 × 316/0.926

V = 0.222/0.926

V = 0.2397L

In mL, volume = 0.2397 × 1000

= 239.7mL

3 0
3 years ago
I am a teacher in a college in a large city in China. One day, some students asked me to join
IrinaVladis [17]

Answer:

c or b

Explanation:

the story is entertaining and it shares the teachers personal experiences with the teachers students

8 0
2 years ago
If you lift an object that weighs 13 pounds through a distance of 3 feet, you have done foot-pounds of work.
Katyanochek1 [597]
The answer to your statement is true 

3 0
3 years ago
Read 2 more answers
The elemental analysis of an organic solid extracted from gum arabic (a gummy substance used in adhesives, inks, and pharmaceuti
Evgesh-ka [11]

Answer:

The molar mass of the organic solid is 120.16 g/mol.

The molecular formula of an organic solid is C_4H_8O_4

Explanation:

Let the molecular mass of an organic solid be C_xH_yO_z

\Delta T_b=K_b\times m

Delta T_b=K_b\times \frac{\text{Mass of solid}}{\text{Molar mass of solid}\times \text{Mass of diphenyl  in Kg}}

where,

\Delta T_f =Elevation in boiling point = =1.5^oC

Mass of organic solid= 0.561 g

Mass of diphenyl = 24.9 g = 0.0249 kg (1 kg = 1000 g)

K_b = boiling point constant = 8.00 °C/m

m = molality

Now put all the given values in this formula, we get

1.5^oC=8.00 ^oC/m\times \frac{0.561 g}{\text{Molar mass of solid}\times 0.0249 kg}

{\text{Molar mass of solid}}=120.16 g/mol

\%=\frac{\text{Number of atoms}\times \text{mass of an atom}}{\text{molas mass of compound}}\times 100

Percentage of carbon in an organic solid = 40.0%

40\%=\frac{x\times 12 g/mol}{120.16 g/mol}\times 100

x = 4.0

Percentage of hydrogen in an organic solid = 6.7%

6.7\%=\frac{y\times 1 g/mol}{120.16 g/mol}\times 100

y = 8.0  

Percentage of hydrogen in an organic solid = 6.7%

53.3\%=\frac{x\times 12 g/mol}{120.16 g/mol}\times 100

y = 4.0

The molecular formula of an organic solid is C_4H_8O_4

8 0
3 years ago
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