Answer:
The answer is (H30+) =3,55e-8M and (OH-)=2,82e-7M
Explanation:
We use the formulas:
pH= - log(H30+) and Kwater=(H30+)x(OH-)
pH= - log(H30+) ----< (H30+)= antilog- pH=antilog- 7,45=3,55E-8M
Kwater=(H30+)x(OH-)
(OH-)=Kwater/(H30+)= 1,00e-14/3,55e-8 = 2,82e-7
Answer:
Explanation:
The chemical equation is:
There are several definitions of acid and bases: Arrhenius', Bronsted-Lowry's and Lewis'.
Bronsted-Lowry model defines and <em>acid</em> as a donor of protons, H⁺.
In the given equation HNO₃ is such substance: it releases an donates its hdyrogen to form the H₃O⁺ ion.
On the other hand, a <em>base</em> is a substance that accepts protons.
In the reaction shown, H₂O accepts the proton from HNO₃ to form H₃O⁺.
Thus, H₂O is a base.
In turn, on the reactant sides the substances can be classified as acids or bases.
H₃O⁺ contain an hydrogen that can be donated and form H₂O; thus, it is an acid (the conjugated acid), and NO₃⁻ can accept a proton to form HNO₃; thus it is a base (the conjugated base).
Balanced equation: N2 + 3H2 ==> 2NH3
moles of NH3 in 240.0 g NH3: 240.0 g x 1 mol/17 g = 14.1 moles
moles N2 needed: 14.1 moles NH3 x 1 mole N2/2 moles NH3 = 7.05 moles N2 needed
grams N2 needed: 7.05 moles x 28 g/mole = 197.4 grams needed :)
sorry what us this i don't get it
