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lesantik [10]
3 years ago
13

Im need some help with this please

Physics
1 answer:
hram777 [196]3 years ago
8 0
The answer is D, human.


Happy Friday!!!
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pychu [463]

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3

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3 years ago
The average intensity of light emerging from a polarizing sheet is 0.775 W/m2, and that of the horizontally polarized light inci
rewona [7]

Answer:

the transmission axis of polarizing sheet makes an angle of \Theta =26.74^{\circ} with the horizontal        

Explanation:

We have given that intensity of light incident on the sheet I_0=0.970W/m^2

Average intensity of light emerging from a polarizing sheet I=0.775W/m^2

We have to find the angle between transmission axis with the horizontal

Intensity of light polarizing from sheet is equal to I=I_0cos^2\Theta

So 0.775=0.970cos^2\Theta

cos^2\Theta =0.798

cos\Theta =0.893

\Theta =26.74^{\circ}

So the transmission axis of polarizing sheet makes an angle of \Theta =26.74^{\circ} with the horizontal

5 0
3 years ago
Babe Ruth steps to the plate and casually points to left centerfield to indicate the location of his next home run. Themighty Ba
Elden [556K]

Answer:

Fs = 32N

Fh = 21 N

Explanation:

Statics

Let Fs be the force of the shoulder, assumed upward

Let Fh be the force of the hand, assumed downward

Sum moments about the hand to zero

1.1(9.8)[67] - Fs[22.5] = 0

Fs = 32N

Sum vertical forces to zero

32 - Fh - 1.1(9.8) = 0

Fh = 21 N

Or we could sum moments about the shoulder point

1.1(9.8)[67 - 22.5] - Fh[22.5] = 0

Fh = 21 N

6 0
3 years ago
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