En un recipiente de cobre de forma rectangular de aproximadamente 3.5 m largo por 4.5m ancho tiene una temperatura en temporada de invierno 4 ° C . Calcular su superficie cuando este en verano a una temperatura 40 ° C . ( Cobre 16.6 x 10 ( -6 )
1 answer:
Answer:
A_f= 15,769 m²
Explanation:
Este es un ejercicio de dilatación térmica,
ΔA = (2α) A₀ ΔT
el arrea de recipiente
A₀ = L A
A₀ = 3,5 4,5
A₀= 15,75 m²
el coeficiente de dilatación térmica es alfa = 16,6 10⁻⁶ C⁻¹
calculemos
ΔA = 2 16,6 10⁻⁶ 15,75 ( 40 -4)
ΔA = 522,9 (36) 10⁻⁶
A= 1,88 10⁻² m2
el cambio de volumen es
ΔA = A_f – A₀
A_f = A₀ + ΔA
A_f= 15,75 +1,88 10⁻²
A_f= 15,769 m²
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