C.Lightweight and durable.
Answer:
The coefficient for PH3 is 8. Option D is correct.
Explanation:
Step 1: The unbalanced equation
P2H4(g) ⇆ PH3(g) + P4(s)
Step 2: Balancing the equation
P2H4(g) ⇆ PH3(g) + P4(s)
On the left side we have 4x H (in P2H4), on the right side we have 3x H (in PH3). To balance the amount of H on both sides, we have to multiply P2H4 on the left side by 3 and PH3 on the right by 4.
3P2H4(g
) ⇆ 4PH3(g) + P4(s)
On the left side we have 6x P (in 3P2H4) on the right side we have 8x P (4x in 4PH3 and 4x in P4). To balance the amount of P on bot hsides, we have to multiply 3P2H4 by 2 and 4PH3 also by 2. Now the equation is balanced
6P2H4(g
) ⇆ 8PH3(g) + P4(s)
The coefficient for PH3 is 8. Option D is correct.
Answer:
Butanoic Acid:
I have attached the structure of Butanoic Acid. Please refer to the attachment.
Explanation:
Solution:
First of all, we need to calculate the double bond equivalent (DBE) for the compound given:
Compound = C4H8O2
DBE = (C +1) - (H + X - N)/2
C = no. of carbons
H = no. of Hydrogen
X = no. of Halogens
N = no. of Nitrogen
DBE = (4+1) - (8/2)
DBE = 5-4
DBE = 1
It indicates the presence of 1 double bond in the possible structure.
Further structure can be identified by looking the peak values of the spectrum. So, we have,
2500 - 3300 = it indicates the presence of -COOH group
1720 = it indicates the (C=0) stretching
1200 = It indicates the (C-O) stretching
SO, the possible structure is
Butanoic Acid:
I have attached the structure of Butanoic Acid. Please refer to the attachment.
Explanation:
this is the answer of your question .
hope it helped you
Particle, Relative Mass<span>, Actual </span>Mass<span> (g) </span>Electron<span>- 1 , 9.11*10 power -28 g. ... Calculate: What is the diff </span>expressed in kg between the mass<span> of a </span>proton and the mass<span> ... Best Answer: </span>difference<span>in </span>mass<span> = [1.673 x 10^(-24) - 9.11 x ...</span>