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jasenka [17]
2 years ago
15

Carbon dioxide fire extinguishers are designed for which types of fuels

Chemistry
1 answer:
Stolb23 [73]2 years ago
3 0

Answer:

Carbon Dioxide is a non-flammable gas that extinguishes fire by displacing oxygen

CO2s are designed for Class B and C (flammable liquid and electrical) fires only.

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You add 28 grams of carbon. You find the actual yield to be 181.2 grams of CO2. What is the percent yield of CO2?
liraira [26]

Answer:

79.14%

Explanation:

Given the equation : 2Fe2O3 + 3C 4Fe + 3C02

The theoretical yield of CO2 ; is 102.6g

Actual yield = 81.2 gram

Percentage yield = (actual yield / theoretical yield) * 100%

Percentage yield = (81.2 / 102.6) * 100%

Percentage yield = 0.7914230 * 100%

Percentage yield = 79.14%

Hence, tbe percentage yield of CO2 is 79.14%

4 0
3 years ago
MODEL Draw a diagram of the soda can calorimeter as a system with energy inputs and
earnstyle [38]

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ARIGATÕ

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3 years ago
Kelly has some sand in a bucket, but she thinks that there may be some salt mixed in with her sand. How can she determine if the
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<span>Kelly has some sand in a bucket, but she thinks that there may be some salt mixed in with her sand. How can she determine if there is salt in the sand?</span><span>

 Answer: If she puts water in the bucket, the salt will dissolve.

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3 0
3 years ago
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Different finch species have beaks of different shapes and sizes. What do these beak differences tell us?
Scorpion4ik [409]

Answer: I think it’s C

Explanation:

I went to bird school where I learned about this stuff.  I’m a little rusty, but I still do good.

4 0
3 years ago
Calculate the amount of heat needed to boil 120.g of acetic acid (HCH3CO2), beginning from a temperature of 16.7°C.
evablogger [386]

Answer:

The total amount of heat needed = 72.2116  kJ

Explanation:

Given that ;

the mass of acetic acid = 120.0 g

The initial temperature T_1 = 16.7 °C  = (16.7 + 273.15 ) K = 298.85 K

The standard molar mass of acetic acid = 60.052  g/mol

Thus ; we can determine the number of moles of acetic acid;

number of moles of acetic acid = mass of acetic acid/ molar mass of acetic acid

number of moles of acetic acid = 120.0 g/ 60.052 g/mol

number of moles of acetic acid =  1.998 moles

For acetic acid:

The standard boiling point  T_2 = 118.1 °C = ( 118.1 + 273.15 ) K = 391.25 K

The enthalpy of vaporization of acetic acid \Delta H_{vap} = 23.7 kJ/mol

The heat capacity of acetic acid   c = 2.043  J/g.K

The change in temperature Δ T = T_2 - T_1

Δ T = (391.25 - 289.85)K

Δ T = 101.4 K

The amount of heat needed to bring the liquid acetic acid at 16.7°C to its boiling point is ;

q = mcΔT

From our values above;

q = 120 g ×  2.043  J/g.K × 101.4 K

q = 24859.2  J

q = 24859 /1000 kJ

q = 24.859 kJ

we have earlier calculated our number of moles o f acetic acid to be 1.998 moles;

Thus;

The needed amount of heat = \Delta_{vap} *numbers \ of  \ moles

The needed amount of heat = 23.7 \ kJ/mol * 1.998 \ moles

The needed amount of heat = 47.3526 kJ

Hence;

The total amount of heat needed = 24.859 kJ + 47.3526 kJ

The total amount of heat needed = 72.2116  kJ

4 0
3 years ago
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