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Neporo4naja [7]
2 years ago
11

Motion Velocity

Physics
1 answer:
Sunny_sXe [5.5K]2 years ago
8 0

Answer:

1. An object is in motion when its distance from another object is changing.

2.Speed is given direction is called velocity.

Speed can be calculated.......

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Answer:The gravitational field on Saturn can be calculated by the following formula;

Explanation:

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4 years ago
Why do different stars have different life cycles
lana66690 [7]
The answer is shape is determined. A stars life cycle is determined in its size
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3 years ago
A teacher lifted a 10 N box and placed it down. Did she do any work? Explain your answer using math
Stells [14]

Answer:

i think it is 45 kilograms not really sure?

Explanation:it might be wrong but i think it is right

8 0
3 years ago
How many photons will be required to raise the temperature of 1.8 g of water by 2.5 k ?'?
tatyana61 [14]
Missing part in the text of the problem: 
"<span>Water is exposed to infrared radiation of wavelength 3.0×10^−6 m"</span>

First we can calculate the amount of energy needed to raise the temperature of the water, which is given by
Q=m C_s \Delta T
where
m=1.8 g is the mass of the water
C_s = 4.18 J/(g K) is the specific heat capacity of the water
\Delta T=2.5 K is the increase in temperature.

Substituting the data, we find
Q=(1.8 g)(4.18 J/(gK))(2.5 K)=18.8 J=E

We know that each photon carries an energy of
E_1 = hf
where h is the Planck constant and f the frequency of the photon. Using the wavelength, we can find the photon frequency:
\lambda =  \frac{c}{f}= \frac{3 \cdot 10^8 m/s}{3 \cdot 10^{-6} m}=1 \cdot 10^{14}Hz

So, the energy of a single photon of this frequency is
E_1 = hf =(6.6 \cdot 10^{-34} J)(1 \cdot 10^{14} Hz)=6.6 \cdot 10^{-20} J

and the number of photons needed is the total energy needed divided by the energy of a single photon:
N= \frac{E}{E_1}= \frac{18.8 J}{6.6 \cdot 10^{-20} J} =2.84 \cdot 10^{20} photons
4 0
3 years ago
The magnitude J of the current density in a certain wire with a circular cross section of radius R = 2.11 mm is given by J = (3.
oksano4ka [1.4K]

Answer:

i = 2.84 \times 10^{-3} A

Explanation:

As we know that current density is ratio of current and area of the crossection

now we have

J = \frac{di}{dA}

so the current through the wire is given as

i = \int J dA

now we have

i = \int_{0.921R}^R J dA

here we have

J = (3.25 \times 10^8)r^2

now plug in the values in above equation

i = \int_{0.921R}^R (3.25 \times 10^8)r^2 2\pi r dr

now we have

i = \int_{0.921R}^R 2\pi (3.25 \times 10^8)r^3 dr

i = (2.04 \times 10^9) \frac{r^4}{4}

now plug in both limits as mentioned

i = (2.04 \times 10^9)(\frac{R^4}{4} - \frac{(0.921R)^4}{4})

i = (2.04\times 10^9)(0.07 R^4)

here R = 2.11 mm

i = (2.04 \times 10^9)(0.07 (2.11 \times 10^{-3})^4)

i = 2.84 \times 10^{-3} A

8 0
3 years ago
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