Answer:
option D
Explanation:
given,
length of the pipe, L = 0.96 m
Speed of sound,v = 345 m/s
Resonating frequency when both the end is open

n is the Harmonic number
2nd overtone = 3rd harmonic
so, here n = 3
now,

f = 540 Hz
The common resonant frequency of the string and the pipe is closest to 540 Hz.
the correct answer is option D
Your grade will probably go down to a D 68% or little higher than that
S = u + at u = 0 278 = 3.7t t = 278/3.7 = 75.135.. v = ut + 0.5at^2 u = 0 v = 0.5 * 3.7 * 75.135^2 = 10,443 m/sec
If,

then, with 3x time t, (suppose, new distance is h)




Therefore, new distance h will be 9 times bigger than distance d.
answer: c
Answer:
changing the direction in which a force is exerted