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3 years ago

Gap region between the diver's skin and her

Physics

1 answer:

Nutka1998 [239]3 years ago

7 0

The energy required by the heating process is 0.042 candy bars.

We'll begin by calculating the mass of the water.

Thickness = 0.5 mm = 0.5 / 1000 = 5×10¯⁴ m
Area = 1 m²
Volume = Area × Thickness = 1 × 5×10¯⁴ = 5×10¯⁴ m³
Density of water = 1000 Kg/m³
Mass of water =?

Mass = Density × Volume

Mass of water = 1000 × 5×10¯⁴

Mass of water = 0.5 Kg

Next, we shall determine the heat required

Mass of water (M) = 0.5 Kg
Initial temperature of water (T₁) = 10 °C
Final temperature (T₂) = 35 °C
Change in temperature (ΔT) = T₂ – T₁ = 35 – 10 = 25 °C
Specific heat capacity of water (C) = 1 Kcal/KgºC
Heat (Q) =?

Q = MCΔT

Q = 0.5 × 1 × 25

Finally, we shall convert 12.5 Kcal to candy bar.

300 Kcal = 1 candy bar

Therefore,

12.5 Kcal = 12.5/300

12.5 Kcal = 0.042 candy bars

Therefore, the energy required in candy bar is 0.042 candy bars

Learn more about heat transfer: brainly.com/question/18883151

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