Answer:
This question is incomplete
Explanation:
This question is incomplete because the result of the described experiment would have better determined the type of scientific explanation to profer. However, the type of material that will preserve the relative hotness or temperature of the hot coffee for the longest time will be a material than can resist heat transfer. These materials tend to keep hot substances hot by not allowing the heat of the coffee to be conducted or pass through it. These materials are mostly insulators or made by placing an insulator between two heat conductors.
Generally, heat is usually transferred from a region of higher concentration to a region of lower concentration, hence when the heat is denied of this transfer, the heat will remain trapped in the "heat-donor" substance (in this case the hot coffee). Thus, the material chosen (A, B or C) will be the material that resists heat transfer the most based on the explanation above.
Answer:
The answer is
<h2>2.00 %</h2>
Explanation:
The percentage error of a certain measurement can be found by using the formula

From the question
actual measurement = 46.37 g
error = 47.25 - 46.37 = 0.88
The percentage error of the measurement is

We have the final answer as
<h3>2.00 %</h3>
Hope this helps you
The concentration of positive charge and mass in Rutherford's atomic model is called the nucleus. Rutherford's experiments involving the use of alpha particle beams directed onto thin metal foils demonstrated the existence of the nucleus. The nucleus of an atom contains positively charge particles called protons and other uncharged particles called neutrons. According to this model most volume of an atom is made up of an empty space.
<u>Answer:</u>
<u>For a:</u> The chemical equation for the dissolution of sodium carbonate is 
<u>For b:</u> The net acid-base reaction is 
<u>Explanation:</u>
Dissolution reaction is defined as the reaction in which a solid compound gets dissolved in water to form aqueous solution.
The chemical equation for the dissolution of sodium carbonate follows:

Ionization reaction is defined as the reaction in which an ionic compound dissociates into its ions when dissolved in aqueous solution.
The chemical equation for the ionization of sodium carbonate follows:

Now, the anion formed which is
reacts with water to form conjugate acid.
The chemical equation for the reaction of anion with water follows:

Hence, the net acid-base reaction of the anion formed and water is written above.
Answer:
for the reaction is -186.75 J/K
Explanation:
Change in entropy (
) for the given reaction under standard condition is given by-
= ![[3\times S_{rhombic}^{0}_{(s)}]+[2\times S_{H_{2}O}^{0}_{(g)}]-[2\times S_{H_{2}S}^{0}_{(g)}]-[1\times S_{SO_{2}}^{0}_{(g)}]](https://tex.z-dn.net/?f=%5B3%5Ctimes%20S_%7Brhombic%7D%5E%7B0%7D_%7B%28s%29%7D%5D%2B%5B2%5Ctimes%20S_%7BH_%7B2%7DO%7D%5E%7B0%7D_%7B%28g%29%7D%5D-%5B2%5Ctimes%20S_%7BH_%7B2%7DS%7D%5E%7B0%7D_%7B%28g%29%7D%5D-%5B1%5Ctimes%20S_%7BSO_%7B2%7D%7D%5E%7B0%7D_%7B%28g%29%7D%5D)
So
=
= -186.75 J/K