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2 years ago

6

-- --- .-. ... . / -.-. --- -.. . / .. ... -. .----. - / - .... .- - / ..-. ..- -. / .- -. -.. / .. .----. -- / ..- ... .. -. --

. / .- / - .-. .- -. ... .-.. .- - --- .-. / - --- --- / ... --- what did I say in Morse code?

1 answer:

Masja [62]2 years ago

4 0

Answer:

MORSE CODE ISN'T THAT FUN AND I'M USING A TRANSLATOR TOO SO

Explanation:

That is what is says in morse code.

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A buret is filled with 0.1517 M naoh A 25.0 mL portion of an unknown acid and two drops of indicator are added to an Erlenmeyer

antiseptic1488 [7]

Answer:

molarity of acid =0.0132 M

Explanation:

We are considering that the unknown acid is monoprotic. Let the acid is HA.

The reaction between NaOH and acid will be:

$NaOH+HA--->NaA+H_{2}O$

Thus one mole of acid will react with one mole of base.

The moles of base reacted = molarity of NaOH X volume of NaOH

The volume of NaOH used = Final burette reading - Initial reading

Volume of NaOH used = 22.50-0.55= 21.95 mL

Moles of NaOH = 0.1517X21.95=3.33 mmole

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3 years ago