Answer:
1.05 V
Explanation:
Since;
E°cell= E°cathode- E°anode
E°cathode= -0.40 V
E°anode= -1.45 V
E°cell= -0.40-(-1.45) = 1.05 V
Equation of the process;
2Zr(s) + 4Cd^2+(aq) ---->2Zr^4+(aq) + 4Cd(s)
n= 8 electrons transferred
From Nernst's equation;
Ecell = E°cell - 0.0592/n log Q
Ecell= E°cell - 0.0592/8 log [0.5]/[0.5]
Since log 1=0
Ecell= E°cell= 1.05 V
Answer:
A radical is a group of atoms of elements carrying a charge, e.g., chlorate [ClO3–]. Radicals or ions are formed by losing or gaining electrons. When an electron is gained the group of atoms acquire a negative charge and is called a negative radical or negative ion.
Glyphosphate stops the production of amino acids which prevents the ribosomes from making proteins
This reaction obeys the law of conservation of mass.
Explanation:
In the burning reaction, methane (CH₄) react with oxygen (O₂) to produce carbon dioxide (CO₂) and water (H₂O):
CH₄ + 2 O₂ → CO₂ + 2 H₂O
Now we calculate the number of moles of methane and carbon dioxide:
number of moles = mass / molar weight
number of moles of methane = 10 / 16.04 = 0.62 moles
number of moles of carbon dioxide = 27 / 44.01 = 0.61 moles
From the chemical reaction we see that 1 mole of methane produces 1 moles of carbon dioxide so 0.6 moles of methane produces 0.6 mole of carbon dioxide. This reaction obeys the law of conservation of mass because the mass of reactants is equal to the mass of products.
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combustion reaction
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Answer:
2.34g of NaCl
Explanation:
HCl(aq) + NaOH(aq) --------> NaCl(aq) + H2O(l)
Number of moles of HCl= 8 × 5/1000= 0.04 moles
Number of moles of NaOH= 2.4 × 20/1000= 0.048 moles
HCl is the limiting reactant
From the balanced reaction equation, 1 mole of HCl produced 58.5g of NaCl
0.04 moles of HCl will produce 0.04 × 58.5 = 2.34g of NaCl
