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antoniya [11.8K]
2 years ago
14

Please help! Mathematics

Mathematics
1 answer:
weeeeeb [17]2 years ago
7 0

Answer:

y = 2

Step-by-step explanation:

Kindly view the attached image to see the rules when looking for the horizontal asymptote.

In this situation we have 2x² / x²

The powers of both are equal to each other therefore the horizontal asymptote will be at the coefficient of the numerator divided by the coefficient of the denominator.

In other words the horizontal asymptote is at y = 2/1 or just 2

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Trapezoid WKLX has vertices W(2, −3), K(4, −3), L(5, −2) , and X(1, −2) . Trapezoid WKLX ​ is translated 4 units right and 3 uni
guapka [62]
Okay, so first of all, if the trapezoid was translated right 4,
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What are the coordinates of the circumcenter of a triangle with vertices A(0,1) B(2,1) and C(2,5)?
yawa3891 [41]
THis is a cool question.
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3 years ago
Two similar circles are shown. The circumference of the larger circle, with radius OB, is 3 times the circumference of the small
zheka24 [161]

Answer:

The circumference of the smaller circle is:

C =  2*pi*x/3

Step-by-step explanation:

We know that for a circle of radius R the circumference is given by:

C = 2*pi*R

where pi = 3.14...

Here we have two circles, A and B, where B is the larger circle and A is the smaller circle.

We know that:

The circumference of B is 3 times the circumference of A.

The radius of circle B is: OB = x

The radius of circle A is: OA

We want to find an expression of OA.

The circumference of circle B will be:

C(B) = 2*pi*OB = 2*pi*x

The circumference of circle A will be:

C(A) = 2*pi*OA

And we know that the circumference of circle B is 3 times the circumference of circle A, then:

C(B) = 3*C(A)

replacing the equations for the circumferences, we get:

2*pi*x = 3*(2*pi*OA)

dividing both sides by 2*pi, we get:

x = 3*OA

Now we want to solve this for OA, then we need to isolate it,

x/3 = OA

We can conclude that the radius of the smaller circle is equal to x/3.

Then the circumference of circle A is:

C(A) = 2*pi*x/3

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