Answer: 11 year
P(1) = 37,100
P(4) = 58,400
The linear equation (for x ≥ 1)
P(x) = 37,100 + a(x-1)
For x = 4
58,400 = 37,100 + a(4-1)
58,400 - 37,100 = 3a
21300 = 3a
a = 7100
So, the linear equation:
P(x) = 37100 + 7100*(x-1)
P(x) = 37100 + 7100x - 7,100
P(x) = 7100x + 30000
To find when the profit should reach 108100, we can substitute P(x) by 108100.
108100 = 7100x + 30000
108100 - 30000 = 7100x
78100 = 7100x
x = 78100/7100
x = 11
Answer: 11 year
Hi Robles928518,
0,1x + 9 ≤ 45
0,1x ≤ 45 - 9
0,1x ≤ 36
x ≤ 360
x ∈ ] - ∞ ; 360 ]
Answer:
one time.
Step-by-step explanation:
Answer:
He could make 16 piles.
Step-by-step explanation:
Divide 48 by 3: 48 ÷ 3 = 16
Tn=3n-5
therefore: T(3)=3(3)-5
T(3) =4
