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swat32
2 years ago
6

How would I do this? A beaker contains 50.0 mL of 0.25 M aluminum nitrate solution. What is the minimum volume of 0.2 M sodium s

ulfide solution that must be added in order to precipitate out all of the aluminum ions from the solution?
Chemistry
1 answer:
Serhud [2]2 years ago
6 0

The minimum volume of 0.2M sodium sulfide that will precipitate out aluminum from 50.0 mL, 0.25 M aluminum nitrate would be 0.094 L or 94 mL

<h3>Stoichiometric calculation</h3>

From the equation of the reaction:

2Al(NO_3)_3 + 3Na_2S ---> Al_2S_3 + 6NaNO_3

Mole ratio of Na2S and Al(NO3)3 = 3:2

Mole of 50.0 mL, 0.25 M Al(NO3)3 = 50/1000 x 0.25

                                                         = 0.0125 mole

Equivalent mole of Na2S = 3/2 x 0.0125

                                         = 0.0188 mole

Volume of 0.2M, 0.0188 mole Na2S = 0.0188/0.2

                                                          = 0.094 L or 94 mL

More on stoichiometric calculations can be found here: brainly.com/question/8062886

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How many grams of calcium chloride would you need to make 1 L of solution containing 5 ppm calcium (Ca)?
Tresset [83]

Explanation:

The given data is as follows.

           Volume = 1 L,    Concentration of Ca = 5 ppm or 5 mg/L

As 1 mg = 0.001 g so, 5 mg /L will be equal to 0.005 g/l. Molar mass of calcium is 40.078 g/mol.

Hence, calculate molarity of calcium as follows.

           Molarity of Ca = \frac{\text{given concentration}}{\text{molar mass}}

                                  = \frac{0.005 g/l}{40.078 g/mol}

         Molarity of Ca = 1.25 \times 10^{-4} M

Hence, molarity of CaCl_{2} is 1.25 \times 10^{-4} M. Since, volume is same so, moles of calcium chloride will be 1.25 \times 10^{-4} mol.

Thus, we can conclude that mass of CaCl_{2} will be as follows.

             1.25 \times 10^{-4} \times 110.984       (molar mass of CaCl_{2} = 110.984 g/mol)

               = 0.0138 g

Thus, we can conclude that mass of CaCl_{2} is 0.0138 g.

4 0
3 years ago
What gets reduced in an electrolytic cell made with nickel and copper electrodes?
jekas [21]

Answer:

D. Ni²⁺  

Explanation:

We know at once that the answer cannot be A or C, because Ni and Cu are already in their lowest oxidation states.

The correct answer must be either B or D.

An electrolytic cell is the opposite of a galvanic cell. In the former, the reaction proceeds spontaneously. In the latter, you must force the reaction to occur.  

One strategy to solve this problem is:

  1. Look up the standard reduction potentials for the half reaction·
  2. Figure out the spontaneous direction.
  3. Write the equation in the reverse direction.

1. Standard reduction potentials

                                E°/V

Cu²⁺ + 2e⁻ ⟶ Cu; 0.3419

Ni²⁺ + 2e⁻ ⟶ Ni;  -0.257

2. Galvanic Cell

We reverse the direction of the more negative half cell and add.

                                       <u>E°/V </u>

Ni ⟶ Ni²⁺ + 2e⁻;           0.257

<u>Cu²⁺ + 2e⁻ ⟶ Cu;      </u>   0.3419

Ni + Cu²⁺ ⟶ Cu + Ni²⁺; 0.599

This is the spontaneous direction.

Cu²⁺ is reduced to Cu.

3. Electrochemical cell

                                        <u>E°/V</u>

Ni²⁺ + 2e⁻ ⟶ Ni;           -0.257

<u>Cu ⟶ Cu²⁺ + 2e⁻;        </u> <u>-0.3419</u>

Cu + Ni²⁺ ⟶ Ni + Cu²⁺; -0.599

This is the non-spontaneous direction.

Ni²⁺ is reduced to Ni in the electrolytic cell.

8 0
3 years ago
What stored information in a cell?
Ede4ka [16]

that would have to be nucleus

4 0
4 years ago
you have accidentally broken a test tube and spilled a chemical on the bench. which of the following best describes what you sho
ANEK [815]

Tell the teacher, do NOT clean it up yourself.

4 0
3 years ago
Consider the equation:
arsen [322]
The first one would be the best answer
4 0
3 years ago
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