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fredd [130]
3 years ago
15

How many valence electrons does tin (Sn) have?​

Chemistry
2 answers:
Vinil7 [7]3 years ago
7 0

Answer:

4 valence electrons

Explanation:

Elena L [17]3 years ago
6 0

Answer:

It has 4 valence electrons

Explanation:

Tin atoms have 50 electrons and 50 protons with 4 valence electrons in the outer shell.

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Jeffry was wondering why when he made breakfast, that after he was done cooking, the mass of everything he used was not the same
12345 [234]

Answer:

equivalent exchange forces cancel out but the  substances are affected around the area

Explanation:

4 0
3 years ago
How does evaporation lead to precipitation​
Serhud [2]

Answer:

1.evaperation

2.condenstation

3.precipatation

Explanation:

So I guess condenstation leads to precipatation-

5 0
3 years ago
Read 2 more answers
Calculate the pH of a solution with an H+ ion concentration of 9.36 x 10-3 M ?
mel-nik [20]

Answer:

The answer is 2.03

Explanation:

The pH of a solution can be found by using the formula

pH = - log [ {H}^{+} ]

where H+ is the Hydrogen ion concentration

From the question we have

pH =  -  log(9.36 \times  {10}^{ - 3} )  \\  = 2.02872415...

We have the final answer as

<h3>2.03 </h3>

Hope this helps you

6 0
3 years ago
Will a precipitate of magnesium fluoride form when 300. mL of 1.1 × 10 –3 M MgCl 2 are added to 500. mL of 1.2 × 10 –3 M NaF? [K
Tju [1.3M]

Answer:

No precipitate is formed.

Explanation:

Hello,

In this case, given the dissociation reaction of magnesium fluoride:

MgF_2(s)\rightleftharpoons Mg^{2+}+2F^-

And the undergoing chemical reaction:

MgCl_2+2NaF\rightarrow MgF_2+2NaCl

We need to compute the yielded moles of magnesium fluoride, but first we need to identify the limiting reactant for which we compute the available moles of magnesium chloride:

n_{MgCl_2}=0.3L*1.1x10^{-3}mol/L=3.3x10^{-4}molMgCl_2

Next, the moles of magnesium chloride consumed by the sodium fluoride:

n_{MgCl_2}^{consumed}=0.5L*1.2x10^{-3}molNaF/L*\frac{1molCaCl_2}{2molNaF} =3x10^{-4}molMgCl_2

Thus, less moles are consumed by the NaF, for which the moles of formed magnesium fluoride are:

n_{MgF_2}=3x10^{-4}molMgCl_2*\frac{1molMgF_2}{1molMgCl_2}=3x10^{-4}molMgF_2

Next, since the magnesium fluoride to magnesium and fluoride ions is in a 1:1 and 1:2 molar ratio, the concentrations of such ions are:

[Mg^{2+}]=\frac{3x10^{-4}molMg^{+2}}{(0.3+0.5)L} =3.75x10^{-4}M

[F^-]=\frac{2*3x10^{-4}molMg^{+2}}{(0.3+0.5)L} =7.5x10^{-4}M

Thereby, the reaction quotient is:

Q=(3.75x10^{-4})(7.5x10^{-4})^2=2.11x10^{-10}

In such a way, since Q<Ksp we say that the ions tend to be formed, so no precipitate is formed.

Regards.

6 0
3 years ago
What does it regulate? One sentence will help!
Mandarinka [93]
<span>a regultate is to control or direct by a rule, principle, or method.</span>
7 0
3 years ago
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