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nydimaria [60]
2 years ago
11

Inside a television picture tube there is a build-up of electrons (charge of 1. 602 × 10–19 C) with an average spacing of 38. 0

nanometers between electrons. Find the electric field inside the picture tube. (Round to three significant figures. ).
Physics
1 answer:
Olin [163]2 years ago
8 0

The magnitude of the electric field inside the picture tube is 998.476 kN/C.

<h3>What is an electric field?</h3>

It is an area in the space where a charged particle experiences a force. It can be calculated by the formula,

E =\dfrac {kQ}{r^2 }

Where,

E = electric field produced

Q = charge =  1.602 \times  10^{-19}\rm \  C

r = distance = 38 \times  10^{-9}\rm \  m

k = Coulomb's constant = 9 \times 10^9 \rm \ N. m2 / C2

Put the values in the formula,

E = \dfrac {9 \times 10^9\times 1.602 \times  10^{-19}}{(38 \times  10^{-9})^2}\\\\E = 998.476 \rm \ kN/C

Therefore, the magnitude of the electric field inside the picture tube is 998.476 kN/C.

Learn more about the electric field:

brainly.com/question/3783640

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