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butalik [34]
3 years ago
7

List all the formulae in Physics

Physics
1 answer:
Alborosie3 years ago
6 0

Answer:

...........

Explanation:

Hope this help u!

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A 0.0663 kg ingot of metal is heated to 241◦C
Westkost [7]

Answer:280.216j/kg°C

Explanation:

Mass of metal=0.0663kg

mass of water=0.395kg

Final temperature=27.4°C

Temperature of metal=241°C

Temperature of water=25°C

specific heat capacity of water=4186j/kg°C

0.0663xax(241-27.4)=0.395x4186x(27.4-25)

0.0663xax213.6=0.395x4186x2.4

14.16168a=3968.328

a=3968.328 ➗ 14.16168

a=280.216j/kg°C

4 0
3 years ago
body starting from rest and moving with an uniform acceleration of 3 m/s²..What is its velocity after 15s?​
Luba_88 [7]
<h2>Answer :</h2>

□ The Final velocity of body = 45 m/s\sf{ }

<h2>Given :</h2>

Initial velocity of body = 0 m/s

Acceleration of body = 3 m/s²

Time taken by body = 15 sec

<h2>To Calculate :</h2>

Final velocity of body = ?

<h2>How To Calculate ?</h2>

<h3>❒ </h3>

Here in this question we are provided that a body is in rest so it's initial velocity will be 0 m/s (because from rest), Acceleration of body is 3 m/s², and Time taken is also given which is 15 sec.

<h3>❒</h3>

 To calculate the Final velocity of body we'll use the first equation of motion which says v = u + at

Where,

  • v is the Final velocity in m/s.

  • u is the Initial velocity in m/s.

  • a is the Acceleration in m/s².

  • t is the Time taken in second.

<h2>Calculation :</h2>

From first equation of motion

  • ⇒ v = u + at

  • ⇒ v = 0 + 3 × 15

  • ⇒ v = 0 + 45

  • ⇒ v = 45

Hence, the Final velocity of body is 45 m/s.

7 0
3 years ago
Read 2 more answers
An electron has a mass of 9.1x10^-31 kg and a charge
Paha777 [63]

is one of these the question

6 0
2 years ago
The potential energy of an object attached to a spring whose elastic constant is k is given by the formula p e space equals spac
Mademuasel [1]
You know the following:
k= 25N/m
x=1.5m
Now you just plug these numbers into the formula which is
Epe = 1/2kx²
       = 1/2(25N/m)(1.5m)²
       =  28.125J or in proper sigdigs 28J 
Hope this helps!
5 0
4 years ago
A ball is thrown vertically upward with a speed of 1.86
Inessa05 [86]

Answer:

t = 1.09 s.

Explanation:

This is a one-dimensional kinematics question, so the equations of kinematics will be sufficient to solve the question.

y-y_0 = v_0t + \frac{1}{2}at^2\\0 - 3.82 = 1.86t +\frac{1}{2}(-9.8)t^2\\-3.82 = 1.86t - \frac{1}{2}9.8t^2\\4.9t^2 - 1.86t - 3.82 = 0

This quadratic equation can be solved using determinant.

\Delta = b^2 - 4ac\\t_{1,2} = \frac{-b \pm \sqrt{\Delta} }{2a}\\t_1 = 1.09~s\\t_2 = -0.71~s

Of course, we will choose the positive time.

4 0
3 years ago
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