Answer:
The recoil velocity is 0.354 m/s.
Explanation:
Given that,
Mass of hunter = 70 kg
Mass of bullet = 42 g = 0.042 kg
Speed of bullet = 590 m/s
We need to calculate the recoil speed of hunter
Using conservation of momentum
Where,
= mass of hunter
= mass of bullet
u = initial velocity
v = recoil velocity
Put the value in the equation
Hence, The recoil velocity is 0.354 m/s.
Assuming that the students
worldwide are being considered, because of the extremely large population, this
can be considered as a binomial distribution. A normal distribution is used most
usually as a fair approximation of the binomial. The mean is the expectation,
therefore:<span>
E[x] = np = (16)(0.22) = 3.52
<span>μ = 3.52 </span></span>
Answer:
V1 =8.1 m/s
Explanation:
height at highest point (h2) = 4.1 m
height at lowest point (h1) = 0.8 m
acceleration due to gravity (g) = 9.8 m/s^{2}
from conservation of energy, the total energy at the lowest point will be the same as the total energy at the highest point. therefore
mgh1 + 
= mgh2 + 
where
- speed at highest point = V2
- speed at lowest point = V1
- mass of the girl and swing = m
- at the highest point, the speed is minimum (V1 = 0)
- at the lowest point the speed is maximum (V2 is the maximum speed)
- therefore the equation becomes mgh1 + = mgh2
m(gh1 + 
) = m(gh2)
gh1 + = gh2
V1 = 
now we can substitute all required values into the equation above.
V1 = 
V1 = 
V1 =8.1 m/s
Answer:
m=image distance÷object distance
The two neutral atoms A and B have the same number of electrons and atomic number 11. So, the two elements are said to be same.
The electronic configuration of the element is the arrangement of the electrons in the atom of the element in energy levels, orbitals around the nucleus.
The electrons in the atoms of the element with lowest energy are written first before those with higher energy levels. Thus, the electronic configuration shows the electrons in the atoms of the element arranged in order of increasing energies.
The electronic configuration of atoms are given as
A = 1s² 2s² 2p⁶ 3s¹
B = 1s² 2s² 2p⁶ 5s¹
The number of electrons in both the elements is 11. Therefore, their atomic number is also the same i.e, 11. So, both the elements are the same.
To know more about atomic number:
brainly.com/question/8645622
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