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butalik [34]
3 years ago
7

List all the formulae in Physics

Physics
1 answer:
Alborosie3 years ago
6 0

Answer:

...........

Explanation:

Hope this help u!

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A speedboat initially at rest accelerates at 4.0 m/s (squared) for 7.0 s. How far does the speedboat move in 7.0 s?
Ulleksa [173]
I think is 3 becuase when he star at 4
4 0
3 years ago
Steam enters a counterflow heat exchanger operating at steady state at 0.07 MPa with a specific enthalpy of 2431.6 kJ/kg and exi
PIT_PIT [208]

Answer:

Explanation:

Given:

Steam Mass rate, ms = 1.5 kg/min

= 1.5 kg/min × 1 min/60 sec

= 0.025 kg/s

Air Mass rate, ma = 100 kg/min

= 100 kg/min × 1 min/60 sec

= 1.67 kg/s

A.

Extracting the specific enthalpy and temperature values from property table of “Saturated water – Pressure table” which corresponds to temperature at 0.07 MPa.

xf, quality = 0.9.

Tsat = 89.9°C

hf = 376.57 kJ/kg

hfg = 2283.38 kJ/kg

Using the equation for specific enthalpy,

hi = hf + (hfg × xf)

= 376.57 + (2283.38 × 0.9)

= 2431.552 kJ/kg

The specific enthalpy of the outlet, h2 = hf

= 376.57 kJ/kg

B.

Rate of enthalpy (heat exchange), Q = mass rate, ms × change in specific enthalpy

= ms × (hi - h2)

= 0.025 × (2431.552 - 376.57)

= 0.025 × 2055.042

= 51.37455 kW

= 51.38 kW.

5 0
3 years ago
(a) Calculate the buoyant force on a 2.00-L helium balloon.
iragen [17]

Answer:

0.0239364 N

0.0057879 N

Explanation:

\rho = Density of the gas

g = Acceleration due to gravity = 9.81 m/s²

V = Volume

Mass of rubber = 1.5 g

Buoyant force is given by

F_b=\rho gV\\\Rightarrow F_b=1.22\times 9.81\times 2\times 10^{-3}\\\Rightarrow F_b=0.0239364\ N

The buoyant force is 0.0239364 N

Net vertical force is given by

F_n=F_b-W_{He}-W_{r}\\\Rightarrow F_n=0.0239364-0.175\times 2\times 10^{-3}\times 9.81-1.5\times 10^{-3}\times 9.81\\\Rightarrow F_n=0.0057879\ N

The net vertical force is 0.0057879 N

6 0
4 years ago
A balloon having an initial temperature of 17.8°C is heated so that the volume doubles while the pressure is kept fixed. What i
Rama09 [41]

Answer:

T = 308.6 ^0 C

Explanation:

Here by ideal gas equation we can say

PV = nRT

now we know that pressure is kept constant here

so we will have

V = \frac{nR}{P} T

since we know that number of moles and pressure is constant here

so we have

\frac{V_2}{V_1} = \frac{T_2}{T_1}

now we know that initial temperature is 17.8 degree C

and finally volume is doubled

So we have

\frac{2V}{V} = \frac{T_2}{(273 + 17.8)}

so final temperature will be

T_2 = 581.6 k

T_2 = 308.6 ^o C

5 0
3 years ago
The mass of M1 = 12 Daltons and it has a speed of v1 = 200 m/s. The mass of M2 = 4 Daltons. What was the total momentum of the s
svet-max [94.6K]

Answer:

The total momentum is  p__{T }} =(2400  -4 v_2) \ Dalton \cdot m/s

Explanation:

The diagram illustration this  system is shown on the first uploaded image (From physics animation)

From the question we are told that

     The mass of the first object is M_1 =  12 \ Dalton

      The speed of the first mass is v_1 =  200 \ m/s

      The mass of the second object is  M_2 =  4 \ Dalton

      The speed of the second object is  assumed to be  - v_2

The total momentum of the system is the combined momentum of both object which is mathematically represented as

           p__{T }} = M_1 v_1 + M_2 v_2

   substituting values

            p__{T }} = 12 * 200 + 4 * (-v_2)

            p__{T }} =(2400  -4 v_2) \ Dalton \cdot m/s

7 0
3 years ago
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