Answer:
0.12 mm ; 140.50 rad/m ; 628.32 rad/sec ; +
Explanation:
Given the wave equation of the form :
y(x, t) = ym sin(kx ± ωt)
Mas per unit length (u) = 5 g/cm = (5÷1000)kg / 0.01m) = 0.005kg/0.01m = 0.5kg/m
Tension, T = 10 N
Amplitude, A = 0.12 mm
Frequency, F = 100 Hz
Comparing with the general wave equation :
y = Asin(kx ± ωt)
A = amplitude = ym = 0.12 mm
2.) k = 2π / λ
Recall :
v = fλ
v = sqrt(T/u) = sqrt(10/0.5) = sqrt(20) = 4.472
λ = v/ f = 4.472 / 100 = 0.04472
Hence,
k = (2 * π) / 0.04472
k = 140.50 rad/m
3.) Angular frequency, ω
ω = 2πf = 2 * 3.14 * 100 = 628.32 rad/sec
4.) sign is +ve
Direction of wave propagation as given is in the negative x axis
Answer:
kinetic energy is 2, 4, 50 thirties, 2.45 into 10, raise to three Julie.
Explanation:
In the given question, we are told that what is the kinetic energy of mass M equals 0.1 kg bullet traveling at a velocity Velocity is given and 700 m/s. So we know that kinetic energy mm-hmm k equals one half m v squared. So this will be mass is given 0.1 and velocity is 700 so 700 square this is one half 0.1 in two 49 double zero, double zero. This is one-half into 49 double zero. So kinetic energy is 2, 4, 50 thirties, 2.45 into 10, raise to three Julie. This is kinetic energy. Thank you.
Answer:
178.888896 m
12790.56 m
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration
The acceleration is
The acceleration is
Distance traveled in the first 8 seconds is 178.888896 m
Distance traveled during 8-60 second interval is 12790.56 m
(a) 
The frequency of a wave is given by:
where
v is the wave's speed
is the wavelength
For the red laser light in this problem, we have
(speed of light)
Substituting,
(b) 427.6 nm
The wavelength of the wave in the glass is given by
where
is the original wavelength of the wave in air
n = 1.48 is the refractive index of glass
Substituting into the formula,
(c) 
The speed of the wave in the glass is given by
where
is the original speed of the wave in air
n = 1.48 is the refractive index of glass
Substituting into the formula,
