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Wittaler [7]
3 years ago
14

What is the maximum of the sinusoidal function?.

Physics
1 answer:
professor190 [17]3 years ago
8 0
The max is the largest it could get so ( ,0)
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The lord of the greeks answer d
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3 years ago
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Look at the diagram below. The value of equivalent resistor is: A. 4 Ω B. 6 Ω C. 8 Ω D. 10 Ω
Advocard [28]

Answer:

R=4Ω

Explanation:

R1 and R3 are parrallel

so we have : R=R1*R2/R1+R2

R=6*3/6+3

R=18/9

R=2Ω

R2 and 2Ω are in series,so we have

R=R2+2

R=2+2

R=4Ω

5 0
3 years ago
The triceps muscle in the back of the upper arm extends the forearm.
iren [92.7K]

To solve this problem it is necessary to apply the concepts related to Torque as a function of Force and distance. Basically the torque is located in the forearm and would be determined by the effective perpendicular lever arm and force, that is

\tau = F \times r

Where,

F = Force

r = Distance

Replacing,

\tau = 2*10^3*0.03

\tau = 60N\cdot m

The moment of inertia of the boxer's forearm can be calculated from the relation between torque and moment of inertia and angular acceleration

\tau = I \alpha

I = Moment of inertia

\alpha = Angular acceleration

Replacing with our values we have that

I = \frac{\tau}{\alpha}

I = \frac{60}{120}

I = 0.5kg\cdot m^2

Therefore the value of moment of inertia is 0.5kg\cdot m^2

8 0
3 years ago
A parallel-plate capacitor is connected to a battery. What happens to the stored energy if the plate separation is doubled while
zlopas [31]

Answer:

new energy of the capacitor is half that of initial energy

Explanation:

As we know that the energy stored in the capacitor is given as

U = \frac{1}{2}CV^2

here we know that capacitance of parallel plate capacitor is given as

C = \frac{\epsilon_0 A}{d}

V = voltage of battery

so now we have capacitor remains connected to the same battery and the separation between the plates is doubled

so we have

C' = \frac{\epsilon_0 A}{2d}

so now the energy stored between the plates is

U = \frac{1}{2}(\frac{C}{2})V^2

so new energy of the capacitor is half

8 0
4 years ago
A train moves from rest to a speed of 30 m/s in 32.0 seconds. What is its acceleration?​
kramer

Answer:

0.94m/s (squared)

Explanation:

a=change in velocity/time

a=v-u/t

a=32-0=32/32

a=0.94m/s (squared)

6 0
3 years ago
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