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NISA [10]
3 years ago
5

Who else loves snowmobiling ​

Physics
2 answers:
devlian [24]3 years ago
4 0
I’ve never went snowmobiling. How is it?
Natalka [10]3 years ago
4 0

Answer:i have never did it but i was in a vr sim an it was soooo cool

Explanation:

i want to try it in real life

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A solid cylindrical object has a mass of 2.0 kg, a diameter
omeli [17]

Answer:

I = 0.0025 kg.m²

Explanation:

Given that

m= 2 kg

Diameter ,d= 0.1 m

Radius ,R=\dfrac{d}{2}

R=\dfrac{0.1}{2}

R=0.05 m

The moment of inertia of the cylinder about it's axis same as the disc and it is given as

I=\dfrac{mR^2}{2}

Now by putting the all values

I=\dfrac{2\times 0.05^2}{2}

I = 0.0025 kg.m²

Therefore we can say that the moment of inertia of the cylinder will be  0.0025 kg.m².

4 0
3 years ago
A passenger travels from the first floor to the 60th floor, a distance of 210 m in 35 s. what is the elevators speed
Sati [7]
  • Distance=210m
  • Time=35s

\\ \tt\bull\leadsto Speed=\dfrac{Distance}{Time}

\\ \tt\bull\leadsto Speed=210/35=6m/s

3 0
3 years ago
Read 2 more answers
A wrench is placed at 30 cm in front of a diverging lens with a focal length of magnitude 10 cm. What is the magnification of th
WARRIOR [948]

Answer:

0.25

Explanation:

Magnification = image distance/object distance

mag = v/u.................. Equation 1

Given: f = -10 cm ( diverging lens) u = 30 cm.

Where can calculate for the value of v using

1/f = 1/u+1/v

make v the subject of the equation

v = fv/(u-f)..................... Equation 2

Substitute into equation 2

v = -30(10)/(30+10)

v = -300/40

v = -7.5 cm.

substituting into equation 1,

mag = 7.5/30

mag = 0.25

hence the magnification of the wretch = 0.25

4 0
3 years ago
A proton starting from rest travels through a potential of 1.0 kV and then moves into a uniform 0.040-T magnetic field directed
Hatshy [7]

Answer:

0.114m

Explanation:

From the general expression for the radius of the proton's resulting orbit, we have

r=\frac{mv}{qB}

where q is is the charge of the proton 1.6*10^{-19}C

m is the mass of the proton  1.67*10^{-27}kg

B is the magnetic field  0.040T

and v i the speed.

to determine the speed, we use the expression

Kinetic Energy=qV

1/2mv^{2}=qV

where <em>V  </em>is the voltage value i.e 1.0kv

and v is the speed

Hence, from simple rearrangement we have the speed v to be

v=\sqrt{\frac{2Vq}{m}} \\

if we substitute value, we have

v=\sqrt{\frac{2*1000*1.6*10^{-19} }{1.67*10^{-27}}} \\

carrying out careful arithmetic we arrive at

v=4.38*10^{5} m/s.

using the value for the speed in the expression for the radius of the orbit as stated earlier, we have

r=\frac{1.67*10^{-27}*4.38*10^{5}}{1.6*10^{-19}*0.04} \\

r=0.114m

7 0
3 years ago
An airplane awaiting departure is cleared to takeoff, its accelerates down a runway at 3.20m/ s2 for 32.8s until it finally lift
stich3 [128]

The final velocity before takeoff is 104.96 m / s.

<u>Explanation:</u>

The last velocity of a given object over some time defines the final velocity. The final velocity of the object is given by the product of acceleration and time and adding this product to the initial velocity.

To calculate the final velocity,

                          V = u + at

where v represents the final velocity,

           u represents the initial velocity,

           a represents the acceleration

            t represents the time taken.

                            v = 0 + (3.20)\times( 32.8)

                            v   = 104.96 m / s.

7 0
3 years ago
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