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Olegator [25]
3 years ago
9

The swimmer in the pool is making waves when he swims. Choose the sentences that describe both the swimmer’s waves and the waves

the worker makes when he hammers on the ladder. Choose the two that apply.
A. They both transfer matter.
B. They both transfer energy.
C. They both are surface waves.
D. They both are transverse waves.
E. They both need matter to travel through.
Physics
1 answer:
devlian [24]3 years ago
3 0

Answer:

B

Explanation:

there moving the waves through energy

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(b) Find the position, velocity, and acceleration of the mass at time t = 5π/6.
Juli2301 [7.4K]
Solution 
x(t) = 8 cos t, x(5π/6)= 8 cos(<span>5π/6)
</span>cos(5π/6)=cos(3π/6 + 2π/6 )=cos(π/3 +π/2)= - sin π/3  (cos (x+<span>π/2)= -sinx)
</span>x(t) = -8sin <span>π/3 = - 4 .sqrt3
</span>v(t) = -8sint = -8sin (π/3 +<span>π/2)= -8 cosπ/3 </span>(sin (x+π/2)= cosx)
v(t) =<span> -8 cosπ/3 = -8/2= - 4 
</span>a(5π/6) = - 8cost = -(- sin π/3)= 4 .<span>sqrt3
</span>a(5π/6) =  4 .<span>sqrt3</span>
4 0
3 years ago
A car traveling on a straight road at 10 meters per second accelerates uniformly to a speed of 21 meters per second in 12 second
labwork [276]
21+10=31 because you can see that 21 and 10 are in metres while 12 is in seconds so 21+10=31 is the answer.
6 0
3 years ago
Which graph shows acceleration? A graph of position (meters) versus time (seconds) has a straight line running from 0 seconds 0
charle [14.2K]

It's the one that has a concave line running upward.

6 0
2 years ago
Read 2 more answers
Round to three significant figures.<br> 0.0785584 rounds to
Elan Coil [88]

Answer:

0.0786

Explanation:

zero after the decimal place is not a significant figure since it comes before the real integer "7".

"5 " in ten thousandth place is rounded off to "6" because the next digit is also another "5",

so we get the three sfg 0.0786

8 0
3 years ago
One mol of a perfect, monatomic gas expands reversibly and isothermally at 300 K from a pressure of 10 atm to a pressure of 2 at
Zolol [24]

Answer:

Explanation:

Given

1 mole of perfect, monoatomic gas

initial Temperature(T_i)=300 K

P_i=10 atm

P_f=2 atm

Work done in iso-thermal process=P_iV_iln\frac{P_i}{P_f}

P_i=initial pressure

P_f=Final Pressure

W=10\times 2.463\times ln\frac{10}{2}=39.64 J

Since it is a iso-thermal process therefore q=w

Therefore q=39.64 J

(b)if the gas expands by the same amount again isotherm-ally and irreversibly

work done is=P\Delta V

V_1=\frac{RT_1}{P_1}=\frac{1\times 0.0821\times 300}{10}=2.463 L

V_2=\frac{RT_2}{P_2}=\frac{1\times 0.0821\times 300}{2}=12.315 L

\Delta W=1\times (12.315-2.463)=9.852 J

\Delta q=\Delta W=9.852 J

\Delta U=0

8 0
3 years ago
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