Question

Consider the following chemical reaction of bromothymol blue indicator. It appears yellow in undissociated form and blue in its dissociated aqueous solution. HC2H3O2(aq) Double headed arrow. H (aq) C2H3O2–(aq) yellow blue What will be the color of the solution if a large amount of H2CO3 is added? The solution will remain yellow. The solution will turn blue. The solution will turn pink. The solution will turn green.

Answer 1

The addition of hydrogen carbonate to bromothymol blue turns the solution blue. Thus, option B is correct.

The balanced equation for the dissociation of bromothymol blue is:

$\rm HC_2H_3O_2\;\leftrightharpoons H^+\;+\;C_2H_3O_2^-$

The color of dissociated form is yellow and undissociated form is blue.

What is the final color of solution?

The addition of hydrogen carbonate results in the dissociated ions as:

$\rm H_2CO_3\;\rightarrow\;2\;H^+\;+\;CO_3^-$

The dissociation results in the increased hydrogen ion concentration. The undissociated form in the reaction mixture increases.

Thus, the color of the solution will turn blue. Hence, option B is correct.

Learn more about bromothymol blue, here:

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