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Harlamova29_29 [7]
3 years ago
7

1. As you increase speed is there an increase or decrease in Kinetic Energy?

Chemistry
1 answer:
drek231 [11]3 years ago
3 0

\qquad \qquad\huge \underline{\boxed{\sf Answer}}

1. As you increase speed is there an increase or decrease in Kinetic Energy?

\qquad \sf  \dashrightarrow \: increase

2. As you increase mass is there an increase or decrease in Kinetic Energy?

<h3 />

\qquad \sf  \dashrightarrow \: increase

3. As you decrease speed is there an increase or decrease in Kinetic Energy?

\qquad \sf  \dashrightarrow \: decrease

4. As you decrease mass is there an increase or decrease in Kinetic Energy?

\qquad \sf  \dashrightarrow \: decrease

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Answer:

to manyneh nrjwsj

Explanation:

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For about how long do scientists think wind and solar power can provide us with energy?
ivanzaharov [21]

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D

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Assuming that the solubility of radon in water with 1 atm pressure of the gas over the water at 30 ∘C is 7.27×10−3M, what is the
Daniel [21]

Answer:

K = 137.55 atm/M.

Explanation:

  • The relationship between gas pressure and the  concentration of dissolved gas is given by  Henry’s law:

<em>P = (K)(C)</em>

where P is the partial pressure of the gaseous  solute above the solution (P = 1.0 atm).

k is a constant (Henry’s constant).

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∴ K = P/C = (1.0 atm)/(7.27 x 10⁻³ M) = 137.55 atm/M.

4 0
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Hypochlorous acid decays in the presence of ultraviolet radiation. Assume that degradation occurs accord- ing to first-order kin
Dennis_Churaev [7]

Answer:

35.75 days

Explanation:

From the given information:

For first-order kinetics, the rate law can be expressed as:

\mathsf{In \dfrac{C}{C_o} = -kt}

Given that:

the rate degradation constant = 0.12 / day

current concentration C = 0.05 mg/L

initial concentration C₀ = 3.65 mg/L

\mathsf{In( \dfrac{0.05}{3.65})= -(0.12) t}

㏑(0.01369863014) = -(0.12) t

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t = -4.29/-0.12

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3 0
3 years ago
A breeder nuclear reactor is a reactor in which nonfissile U-238 is converted into fissile Pu-239. The process involves bombardm
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<u>Answer:</u> The nuclear equations for the given process is written below.

<u>Explanation:</u>

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_{92}^{238}\textrm{U}+n\rightarrow _{92}^{239}\textrm{U}

Beta decay is defined as the process in which neutrons get converted into an electron and a proton. The released electron is known as the beta particle.

_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta

The chemical equation for the first beta decay process of _{92}^{239}\textrm{U} follows:

_{92}^{239}\textrm{U}\rightarrow _{93}^{239}\textrm{Np}+_{-1}^0\beta

The chemical equation for the second beta decay process of _{93}^{239}\textrm{Np} follows:

_{93}^{239}\textrm{Np}\rightarrow _{94}^{239}\textrm{Pu}+_{-1}^0\beta

Hence, the nuclear equations for the given process is written above.

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