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Naya [18.7K]
2 years ago
14

What happens when a neutral object is brought near a positive object?

Chemistry
2 answers:
NARA [144]2 years ago
5 0

Answer:

If a positively charged body is brought near to a neutral or uncharged body, it induces a negative charge on the near side and a positive charge on the far side of the neutral object. This creates a force of attraction between the two bodies.

snow_tiger [21]2 years ago
4 0

Answer:

stick together like magnets

Explanation:

You might be interested in
What is the total number of grams of mg consumed when 0.50 mole of h2 is produced
rosijanka [135]

Answer:

12 grams

<em>Please mark as Brainliest :)</em>

4 0
2 years ago
In the laboratory you dissolve 13.9 g of potassium phosphatein a volumetric flask and add water to a total volume of 250mL.
tensa zangetsu [6.8K]

Answer:

Molarity of the solution? 0,262 M.

Concentration of the potassium cation? 0,786 M.

Concentration of the phosphate anion? 0,262 M.

Explanation:

Potassium phosphate (K₃PO₄; 212,27 g/mol) dissolves in water thus:

K₃PO₄ → 3 K⁺ + PO₄³⁻ <em>(1)</em>

Molarity is an unit of chemical concentration given in moles of solute (K₃PO₄) per liters of solution.

There are 250 mL of solution≡0,25 L

The moles of K₃PO₄ are:

13,9 g of K₃PO₄ ×\frac{1mol}{212,27 g} = 0,0655 moles of K₃PO₄

The molarity of the solution is:

\frac{0,0655 moles}{0,25L} = 0,262 M

In (1) you can see that 1 mole of K₃PO₄ produces 3 moles of potassium cation. The moles of potassium cation are:

0,0655 moles×3 = 0,1965 moles

The concentration is:

\frac{0,1965 moles}{0,25L} = 0,786 M

The moles of K₃PO₄ are the same than moles of PO₄³⁻, thus, concentration of phosphate anion is the same than concentration of K₃PO₄. 0,262 M

I hope it helps!

4 0
3 years ago
10. A 2.36-gram sample of NaHCO3 was completely decomposed in an
Airida [17]

Answer:

0.79 g

Explanation:

Let's introduce a strategy needed to solve any similar problem like this:

  • Apply the mass conservation law (assuming that this reaction goes 100 % to completion): the total mass of the reactants should be equal to the total mass of the products.

Based on the mass conservation law, we need to identify the reactants first. Our only reactant is sodium bicarbonate, so the total mass of the reactants is:

m_r=m_{NaHCO_3}=2.36 g

We have two products formed, sodium carbonate and carbonic acid. This implies that the total mass of the products is:

m_p=m_{Na_2CO_3}+m_{H_2CO_3}

Apply the law of mass conservation:

m_r=m_p

Substitute the given variables:

m_{NaHCO_3}=m_{Na_2CO_3}+m_{H_2CO_3}

Rearrange for the mass of carbonic acid:

m_{H_2CO_3}=m_{NaHCO_3}-m_{Na_2CO_3}=2.36 g - 1.57 g=0.79 g

8 0
4 years ago
igneous rock that cools very quickly when it forms may have a texture that is______and______with no visible____
Fudgin [204]
<span>Igneous rock that cools very quickly when it forms may have a texture that is smooth and shiny with no visible grain.</span>
6 0
3 years ago
At the beginning of an experiment, a scientist has 176 grams of radioactive goo. After 165 minutes, her sample has decayed to 5.
Paul [167]
The half-life equation is written as:

An = Aoe^-kt

We use this equation for the solution. We do as follows:

5.5 = 176e^-k(165)
k = 0.02
<span>What is the half-life of the goo in minutes? 
</span>
0.5 = e^-0.02t
t = 34.66 minutes <----HALF-LIFE


Find a formula for G(t) , the amount of goo remaining at time t.G(t)=? 

G(t) = 176e^-0.02t

How many grams of goo will remain after 50 minutes? 

G(t) = 176e^-0.02(50) = 64.75 g
6 0
3 years ago
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