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patriot [66]
4 years ago
12

You've just solved a problem and the answer is the mass of an electron, me=9.11×10−31kilograms. How would you enter this number

into the answer box? Enter your answer in kilograms using three significant figures. Note that the units are provided for you to the right of the answer box.
Chemistry
1 answer:
irina1246 [14]4 years ago
7 0

Answer: 9.11\times 10^{-31}kg

Explanation:

Significant figures : The figures in a number which express the value or the magnitude of a quantity to a specific degree of accuracy is known as significant digits.

Rules for significant figures:

Digits from 1 to 9 are always significant and have infinite number of significant figures.

All non-zero numbers are always significant.

All zero’s between integers are always significant.

All zero’s after the decimal point are always significant.

All zero’s preceding the first integers are never significant.

Thus 9.11\times 10^{-31}kg has three significant figures

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In a solution that is 90% ethyl alcohol and 10% water, the solute is and the solvent is . g
babunello [35]

In a solution that is 90% ethyl alcohol and 10% water, the solute is 10 g and the solvent is 90 g.

given that :

The solute in the solution  by mass percent = 10 %

mass percent = ( mass of solute / mass of solution ) × 100%

mass of solute in the solution is  = 10 g

The solvent present in solution by mass percent = 90 %

the mass of solvent in the solution is is 90 g

Thus, In a solution that is 90% ethyl alcohol and 10% water, the solute is 10 g and the solvent is 90 g.

To learn more about solute and solvent here

brainly.com/question/7932885

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2 years ago
ANSWER THIS QUESTION AND GET 10 POINTS AND BRAINLEST
Gelneren [198K]

Answer:

A.All Mixtures Are Made Up Of Solutions

Explanation:

4 0
3 years ago
What is the concentration in molarity of S2O32- (aq) in a solution prepared by mixing 150 mLmL of 0.149 MM Na2S2O3 (aq) with eno
Artist 52 [7]

Answer:

0.0890 M

Explanation:

Since the concentration of KCl is irrelevant in this case, the concentration of Na2S2O3 can be determined using a simple dilution equation:

C1V1 = C2V2, where C1 = 0.149 M, V1 = 150 mL, V2 = 250 mL

C2 = 0.149 x 150/250

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To determine the concentration of  S2O32- (aq), consider the equation:

Na_2S_2O_3  => 2Na^+_{(aq)} + S_2O^2^-_3_{(aq)}

The concentration of Na2S2O3 and S2O32- (aq) is 1:1

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To 3 significant figures = 0.0890 M

7 0
3 years ago
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ololo11 [35]

Answer:

A

Explanation:

5 0
3 years ago
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The following chemical reaction takes place in aqueous solution:
lisabon 2012 [21]

The net ionic equation : Ag⁺(aq)+l⁻(aq) ⇒ Agl(s)

<h3>Further explanation</h3>

Given

Reaction

AgF(aq)+Nal(aq) ——> Agl(s)+NaF(aq)

Required

The net ionic equation

Solution

The equation of a chemical reaction can be expressed in the equation of the ions

In the ion equation, there is a spectator ion that is the ion that does not react because it is present before and after the reaction  

When these ions are removed, the ionic equation is called the net ionic equation  

AgF(aq)+Nal(aq) ——> Agl(s)+NaF(aq)

Ag⁺(aq)+F⁻(aq)+Na⁺(aq)+l⁻(aq) ⇒ Agl(s)+Na⁺(aq) + F⁻(aq)

<em>Ag⁺(aq)+l⁻(aq) ⇒ Agl(s)</em>

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3 years ago
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