<u>Answer:</u> The p-function of
and
ions are 2.51 and 2.14 respectively.
<u>Explanation:</u>
p-function is defined as the negative logarithm of any concentration.
We are given:
Millimolar concentration of zinc nitrate = 3.1 mM
Millimolar concentration of calcium nitrate = 4.2 mM
Converting this into molar concentration, we use the conversion factor:
1 M = 1000 mM
- Concentration of zinc nitrate = 0.0031 M = 0.0031 mol/L
1 mole of zinc nitrate produces 1 mole of zinc ions and 2 moles of nitrate ions
Concentration of zinc ions = 0.0031 M
Concentration of nitrate ions in zinc nitrate, 
- Concentration of calcium nitrate = 0.0042 M = 0.0042 mol/L
1 mole of calcium nitrate produces 1 mole of calcium ions and 2 moles of nitrate ions
Concentration of calcium ions = 0.0042 M
Concentration of nitrate ions in calcium nitrate, 
To calculate the concentration of nitrate ions in the solution, we use the equation:

Putting values in above equation, we get:

Calculating the p-function of zinc ions and nitrate ions in the solution:
![\text{p-function of }Zn^{2+}\text{ ions}=-\log[Zn^{2+}]](https://tex.z-dn.net/?f=%5Ctext%7Bp-function%20of%20%7DZn%5E%7B2%2B%7D%5Ctext%7B%20ions%7D%3D-%5Clog%5BZn%5E%7B2%2B%7D%5D)

![\text{p-function of }NO_3^{-}\text{ ions}=-\log[NO_3^{-}]](https://tex.z-dn.net/?f=%5Ctext%7Bp-function%20of%20%7DNO_3%5E%7B-%7D%5Ctext%7B%20ions%7D%3D-%5Clog%5BNO_3%5E%7B-%7D%5D)

Hence, the p-function of
and
ions are 2.51 and 2.14 respectively.