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irina [24]
2 years ago
8

3. Solve the following problems. Work must be shown in order to earn credit.

Chemistry
1 answer:
madreJ [45]2 years ago
4 0
C. A container of mixed gases is 20.9 C I hope this helps
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Which substance would have the highest melting point, based on electronegativity?
Mazyrski [523]

Answer:

H₂O

Explanation:

Based electronegativity, water H₂O will have the higher melting point from the given choices. The binding force between hydrogen and oxygen is greater than for the others.

  • In group 6, oxygen has the highest electronegativity.
  • It pulls the shared electron closer in the bond.
  • The high electronegativity between hydrogen and oxygen causes the elevated melting point between the two species.  
5 0
3 years ago
32. Barium sulfate, BaSO4, is a white crystalline solid that is insoluble in water. It is used by doctors to diagnose
DIA [1.3K]

Answer:

42

Explanation:

bygyytrdesf

7 0
2 years ago
7. Ionic bonds are at one end of the bond spectrum. What kinds of bonds are at the other end?
blondinia [14]

Answer:

non-polar covalent bonds

this is when the electronegativity difference between the two non-metal atoms is very little to cause a partial charge (delta positive and delta negative; δ+ and δ-) on the atoms

4 0
2 years ago
How many moles of oxygen atoms are present in 5 H20
Vlad1618 [11]

Answer:

1 i guess thats all i could do sorry not to good at math i probs got this wrong

Explanation:

4 0
3 years ago
Read 2 more answers
Consider the chemical equation. 2H2 + O2 mc022-1.jpg 2H2O What is the percent yield of H2O if 87.0 g of H2O is produced by combi
ch4aika [34]

Answer:

88.50 %

The balance chemical equation is as follow,

2 H₂ + O₂ → 2 H₂O

Step 1: Find the limiting reactant;

According to eq.

4.032 g (2 mole) H₂ reacts with = 32 g (1 mole) of O₂

So,

11 g of H₂ will react with = X g of O₂

Solving for X,

X = (11 g × 32 g) ÷ 4.032 g

X = 87.301 g of O₂

Therefore, H₂ is the limiting reactant as O₂ is present in excess.

Step 2: Calculating %age Yield;

According to eq.

4.032 g (2 mole) H₂ produces = 36.032 g (1 mole) of H₂O

So,

11 g of H₂ will react with = X g of H₂O

Solving for X,

X = (11 g × 36.032 g) ÷ 4.032 g

X = 98.301 g of H₂O

So,

Actual Yield = 87 g

Theoretical Yield = 98.301 g

Using formula = Actual Yield / Theoretical Yield × 100

= 87 g / 98.301 × 100

= 88.50 %

4 0
3 years ago
Read 2 more answers
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