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mariarad [96]
2 years ago
7

Use bond enthalpy values to calculate the enthalpy change for the following reaction. Then, label if the reaction is endothermic

or exothermic. 1) CH4 (g) + Br2 (g) --> CH3Br (g) + HBr (g)​

Chemistry
1 answer:
Mila [183]2 years ago
7 0

Based on the bond energies given, the enthalpy change for the reaction of is -33 kJ and the reaction is exothermic.

<h3>What is the change in bond energy of a reaction?</h3>

The change in bond energy of a reaction is calculated using the formula below:

  • change in bond energy = sum of energies of bonds broken - sum of energies of bonds formed

A reaction is exothermic if the change in bond energy is negative.

A reaction is endothermic if the change in bond energy is positive.

Given the bond enery values above:

sum of energies of bonds broken = 4 × C-H + Br-Br

sum of energies of bonds broken = 4 × 413 + 193 = 1845 kJ

sum of energies of bonds formed = 3 × C-H + C-Br + H-Br

sum of energies of bonds formed = 3 × 413 + 276 + 363 = 1878 kJ

Thus;

change in bond energy = 1845 - 1878 = -33 kJ

  • The reaction is exothermic because the change in bond energy is negative.

Therefore, the enthalpy change for the reaction of is -33 kJ and the reaction is exothermic.

Learn more about enthalpy change at: brainly.com/question/11628413

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What is the volume, in liters, of 0.500 mol of c3h8 gas at stp? (hint..use avogadro’s principle to solve this)?
wolverine [178]
When we are at STP conditions, we can use this conversion: 1 mol= 22.4 L

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3 0
3 years ago
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How many molecules are in 7.62 L of CH4, at 87.5°C and 722 torr
pickupchik [31]

Answer: There are 1.469 \times 10^{23} molecules present in 7.62 L of CH_4 at 87.5^{o}C and 722 torr.

Explanation:

Given : Volume = 7.62 L

Temperature = 87.5^{o}C = (87.5 + 273) K = 360.5 K

Pressure = 722 torr

1 torr = 0.00131579

Converting torr into atm as follows.

722 torr = 722 torr \times \frac{0.00131579 atm}{1 torr}\\= 0.95 atm

Therefore, using the ideal gas equation the number of moles are calculated as follows.

PV = nRT

where,

P = pressure

V = volume

n = number of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

PV = nRT\\0.95 atm \times 7.62 L = n \times 0.0821 L atm/mol K \times 360.5 K\\n = \frac{0.95 atm \times 7.62 L}{0.0821 L atm/mol K \times 360.5 K}\\= \frac{7.239}{29.59705}\\= 0.244 mol

According to the mole concept, 1 mole of every substance contains 6.022 \times 10^{23} atoms. Hence, number of atoms or molecules present in 0.244 mol are calculated as follows.

0.244 mol \times 6.022 \times 10^{23}\\= 1.469 \times 10^{23}

Thus, we can conclude that there are 1.469 \times 10^{23} molecules present in 7.62 L of CH_4 at 87.5^{o}C and 722 torr.

5 0
2 years ago
How many grams of NO can be produced from the following reaction if 68.2 grams of NO2 is consumed?
Semenov [28]

Answer:

Option 4. 14.8 g

Explanation:

3NO2 + H2O → 2HNO3 + NO

First let us calculate the molar mass of NO2 and NO. This is illustrated below;

Molar Mass of NO2 = 14 + (2x16) = 14 + 32 = 46g/mol

Mass of NO2 from the question = 3 x 46 = 138g.

Molar Mass of NO = 14 +16 = 30g/mol

From the equation,

138g of NO2 reacted to produce 30g of NO

Therefore, 68.2g of NO2 will react to produce = (68.2 x 30)/138 = 14.8g of NO.

3 0
3 years ago
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