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mariarad [96]
3 years ago
7

Use bond enthalpy values to calculate the enthalpy change for the following reaction. Then, label if the reaction is endothermic

or exothermic. 1) CH4 (g) + Br2 (g) --> CH3Br (g) + HBr (g)​

Chemistry
1 answer:
Mila [183]3 years ago
7 0

Based on the bond energies given, the enthalpy change for the reaction of is -33 kJ and the reaction is exothermic.

<h3>What is the change in bond energy of a reaction?</h3>

The change in bond energy of a reaction is calculated using the formula below:

  • change in bond energy = sum of energies of bonds broken - sum of energies of bonds formed

A reaction is exothermic if the change in bond energy is negative.

A reaction is endothermic if the change in bond energy is positive.

Given the bond enery values above:

sum of energies of bonds broken = 4 × C-H + Br-Br

sum of energies of bonds broken = 4 × 413 + 193 = 1845 kJ

sum of energies of bonds formed = 3 × C-H + C-Br + H-Br

sum of energies of bonds formed = 3 × 413 + 276 + 363 = 1878 kJ

Thus;

change in bond energy = 1845 - 1878 = -33 kJ

  • The reaction is exothermic because the change in bond energy is negative.

Therefore, the enthalpy change for the reaction of is -33 kJ and the reaction is exothermic.

Learn more about enthalpy change at: brainly.com/question/11628413

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12.5 g of copper are reacted with an excess of chlorine gas, and 25.4 g of copper(II) chloride are
Alika [10]

Answer:

Percent yield = 94.5%

Theoretical yield =  26.89 g

Explanation:

Given data:

Mass of copper = 12.5 g

Mass of copper chloride produced = 25.4 g

Theoretical yield = ?

Percent yield = ?

Solution:

Cu + Cl₂  →  CuCl₂

Number of moles of Copper:

Number of moles = mass/ molar mass

Number of moles = 12.5 g/ 63.55 g/mol

Number of moles = 0.2 mol

Now we will compare the moles of copper with copper chloride.

          Cu          :           CuCl₂

           1             :              1

          0.2          :            0.2

Theoretical yield:

Mass of copper chloride:

Mass = Number of moles × molar mass

Mass = 0.2 mol × 134.45 g/mol

Mass = 26.89 g

Percent yield:

Percent yield = Actual yield / theoretical yield  × 100

Percent yield = 25.4 g/26.89 g × 100

Percent yield = 94.5%

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