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Ymorist [56]
2 years ago
15

Write the formulas for the following ionic compounds.

Chemistry
1 answer:
valentinak56 [21]2 years ago
8 0

Answer:

1) KI

2) Mg3P2

3) Ag2S

4) FeBr3

5) Mg(OH)2

6) Na2SO4

7) Pb(NO3)4

8) (NH4)2CO3

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Gnoma [55]

Answer:

Option 2, 3, and also 6 btw

Explanation:

The other guy was wrong

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2 years ago
Conservation of mass to balance the following reaction. Na2S+ KI= NaI+ K2S
lesantik [10]

Answer:

1+2=2+1 is the answer for the question

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cboxed%7B%5Crm%7BChemistry%20%5C%20Question%7D%7D" id="TexFormula1" title="\boxed{\rm{Chemis
shepuryov [24]

Answer:

Explanation:

All three lighter boron trihalides, BX3 (X = F, Cl, Br), form stable adducts with common Lewis bases. Their relative Lewis acidities can be evaluated in terms of the relative exothermicities of the adduct-forming reaction. Such measurements have revealed the following sequence for the Lewis acidity: BF3 < BCl3 < BBr3 (in other words, BBr3 is the strongest Lewis acid).

This trend is commonly attributed to the degree of π-bonding in the planar boron trihalide that would be lost upon pyramidalization (the conversion of the trigonal planar geometry to a tetrahedral one) of the BX3 molecule, which follows this trend: BF3 > BCl3 > BBr3 (that is, BBr3 is the most easily pyramidalized). The criteria for evaluating the relative strength of π-bonding are not clear, however. One suggestion is that the F atom is small compared to the larger Cl and Br atoms, and the lone pair electron in the 2pzorbital of F is readily and easily donated, and overlaps with the empty 2pz orbital of boron. As a result, the [latex]\pi[/latex] donation of F is greater than that of Cl or Br. In an alternative explanation, the low Lewis acidity for BF3 is attributed to the relative weakness of the bond in the adducts F3B-L.

3 0
2 years ago
Read 2 more answers
I need help on this plsss
Firlakuza [10]

Answer:

An engine that creates ignites fuel with highly compressed air.

6 0
3 years ago
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What is the pressure of a sample of gas at a volume of .335 L if it occupies 1700 mL at 850 mm Hg?
dangina [55]

Answer:

Pressure = 4313.43mmHg

Explanation:

P1 = ?

V1 = 0.335L

V2 = 1700mL =1700*10^-3L = 1.7L

P2 = 850mmhg

From Boyle's law, the volume of a fixed mass of gas is inversely proportional to its pressure provided that temperature remains constant.

P = k / v

K = pv. P1V1 = P2V2 = P3V3 =........=PnVn

P1V1 = P2V2

Solve for P1,

P1 = (P2*V2) / V1

P1 = (850 * 1.7) / 0.335

P1 = 4313.43mmHg

The pressure of the gas was 4313.43mmHg

7 0
3 years ago
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