Answer:
E = 1/2 M V^2 + 1/2 I ω^2 = 1/2 M V^2 + 1/2 I V^2 / R^2
E = 1/2 M V^2 (1 + I / (M R^2))
For a cylinder I = M R^2
For a sphere I = 2/3 M R^2
E(cylinder) = 1 + 1 = 2 omitting the 1/2 M V^2
E(sphere) = 1 + 2/3 = 1.67
E(cylinder) / E(sphere) = 2 / 1.67 = 1.2
The cylinder initially has 1.20 the energy of the sphere
The PE attained is proportional to the initial KE
H(sphere) = 2.87 / 1/2 = 2.40 m since it has less initial KE
yes we could its just that the star is most likely dead when we see it i know we can see a star like this because even if the star dies the light is still traveling, like if you went on a drive away from your home and then your home is destroyed just as you leave, just because you house is gone does not mean you cant still travel.
Answer:
1 The hand is moving at a steady up and down motion.
2 The green dot is moving in a trait up and down motion
3 It is moving in a waving and calming motion
Explanation:
The coefficient of kinetic friction between the block and the incline is 0.168.
<h3>
Coefficient of kinetic friction</h3>
The coefficient of kinetic friction is determined from the principle of conservation of energy as follows;
distance traveled on the incline = L
L = h/sin35
L = 1.743 h
Since it takes twice the time travel down,
velocity to slide = 1.743 h/2t = 0.871 v
- v is the velocity to drop from the vertical height
K.E of the block when it slides = ¹/₂mv₁² = ¹/₂m(0.871v)² = 0.871²(K.E to fall) = 0.758K.E to fall straight down
<h3>Energy lost to friction</h3>
1 - 0.758 = 0.24
<h3>Conservation of energy</h3>
μmgcos(35) = 0.24(mgsin(35)
μcos(35) = 0.24(sin(35)
μ = 0.168
Learn more about coefficient of kinetic friction here: brainly.com/question/20241845
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