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statuscvo [17]
2 years ago
12

If x > 2, find lx-2l Help pleaseee

Mathematics
1 answer:
Lyrx [107]2 years ago
8 0
<h3>Answer:  x-2</h3>

Explanation:

If x > 2, then x-2 > 0 after subtracting 2 from both sides.

Since x-2 is always positive when x > 2, this means the absolute value bars around the x-2 aren't needed. The results of |x-2| and x-2 are perfectly identical.

For example, if we tried something like x = 5, then

  • x-2 = 5-2 = 3
  • |x-2| = |5-2| = |3| = 3

Both outcomes are 3. I'll let you try other x inputs.

So because |x-2| and x-2 are identical, this means |x-2| = x-2 for all x > 2.

In short, we just erase the absolute value bars.

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If h(x)=(fog)(x) and h(x)=³√x+3, find g(x) if f(x) =³√x+2
ipn [44]

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The problem:

Find g(x) if h(x)=(f \circ g)(x),

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Step-by-step explanation:

h(x)=(f \circ g)(x)

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Replace x in f(x)=\sqrt[3]{x+2} with g(x) since we are asked to find f(g(x)):

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Let's check:

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