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Viefleur [7K]
3 years ago
5

Find any domain restrictions on the given rational equation

Mathematics
2 answers:
rodikova [14]3 years ago
4 0

Answer:

x ≠ -4, -1, 3

Step-by-step explanation:

\frac{x}{x+4}+ \frac{12}{x^2}  +5x+4 = \frac{8x}{5x-15}

12/(x^2+5x+4) = 8x/(5x-15)

\frac{12}{((x+1)(x+4))}  = \frac{8x}{(5(x-3))}

horrorfan [7]3 years ago
4 0

\\ \tt\hookrightarrow \dfrac{x}{x+4}+\dfrac{12}{x^2+5x+4}=\dfrac{8x}{5x-15}

\\ \tt\hookrightarrow \dfrac{x}{x+4}+\dfrac{12}{(x+1)(x+4)}=\dfrac{8x}{5(x-3)}

  • For x=-4 First fraction becomes undefined
  • For x=-1 second fraction becomes undefined
  • For x=3 third fraction also becomes undefined

So Domain=(-4,-1,3)

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Find f(-1) if f(x) = -3x - 5.<br><br> -9<br><br> 2<br><br> -2<br><br> -8
Svetach [21]
Replace the x

f(-1) = -3(-1) - 5

Negatives turn to positive when multiplied with each other.

f(-1) = 3 - 5

f(-1) = -2
4 0
3 years ago
In a usually right-angled (x, y, z)-coordinate system, three planes are given by the following system of linear equations:
never [62]

Answer:

a) (x, y, z) = (1, -1, 0)

b) a = 0; L = {t, t, 0}

c) a = 1 . . or . . a = 3

d) No

Step-by-step explanation:

a) The solution using row-reduction techniques is shown in the first attachment, part (a). The generic solution is shown evaluated for a=2, the result being (1, -1, 0).

You will note that the solution gives indeterminate values for a=1 and a=3, which make the denominators zero.

b) For this, we use the point solution of part (a) together with the cross product of the normal vectors of planes 1 and 2. Said cross product will be in the direction of their line of intersection. We substitute the parametric equation for that line into the equation for plane 3 and solve for <em>a</em>. The result is a = 0.

The simplification of the resulting equation also gives a=1 and a=3, but we treat those as extraneous solutions because the corresponding common point of intersection of the planes does not exist.

c) The values a = 1 and a = 3 were found in part (a). These are values of <em>a</em> that make the common point indeterminate.

d) Substituting the given values for (x, y, z) gives three equations for <em>a</em> that have 3 different solutions. Hence there cannot be a value of <em>a</em> that makes this be a common point of intersection.

e) The second attachment illustrates part (a), with <em>a</em>=2. The third attachment illustrates part (b) with <em>a</em>=0.

The fourth attachment illustrates part (c). The first picture has the triangular tunnel between the planes in a vertical orientation (<em>a</em>=1). The second picture has the triangular tunnel extending from lower front to upper back (<em>a</em>=3).

7 0
3 years ago
An observer (O) spots a plane (P) taking off from a local airport and flying at a 33° angle horizontal to her line of sight and
lana [24]

Answer:

Option D. 10,779 feet

Step-by-step explanation:

Given from the figure attached,

PT = OB = 7000 ft

PB = OT = x feet

and angle of elevation (∠POT) = 30°

By applying Tan rule in the triangle POT,

tan33° = \frac{\text{Opposite side}}{\text{Adjacent side}} = \frac{PT}{OT}

tan33° = \frac{7000}{x}

x = \frac{7000}{\text{tan}33}

x = 10779 feet

Therefore, distance between the bird (B) and plane (P) is 10,779 feet.

Option D. will be the answer.

3 0
3 years ago
What is the range of the reciprocal function ?
melamori03 [73]

Answer:

B

Step-by-step explanation:

The range is the set of y-values for which the function is defined.

** Attached is the graph of the function

By looking at the graph, we can clearly see that there aren't any y-values that is not permitted in the graph. The function is defined for all y-values. Hence the range is set of all real numbers, or, the range is (-∞, +∞)

Answer choice B is right.

7 0
3 years ago
How do I solve 8/9x=8+4/9x
zhuklara [117]
You subtract 4/9x frm 8/9x which is 4/9x = 8 then you multiply 9 to 8 so it is 4x = 72. After that, you divide 4 from 72 and get 18
4 0
3 years ago
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