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cluponka [151]
3 years ago
13

Which element has the largest atom phosphorus, sulfur, chlorine, or fluorine

Chemistry
1 answer:
monitta3 years ago
3 0

Answer:

Chlorine

Explanation:

It has the greatest mass out of the elements listed

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10. The diagram below shows the sun, Earth, and the moon.
kotykmax [81]

Answer:

I think a lunar eclipse

5 0
3 years ago
Read 2 more answers
If the molarity of sugar is 1.1, what will the freezing point be?
Ganezh [65]

Answer:

The freezing point will be -2.046°C.

Explanation:

The freezing point depression equation is \Delta T_f = k_f \cdot m \cdot i

Where;

\Delta T_f = The temperature depression of the freezing point

k_f= The constant of freezing point depression which is solvent dependent = 1.86°C/m

i = The number of particles the substance decomposes into in solution = 1 for sugar (a covalent compound)

m = The molality of the solution = 1.1

Therefore, we have;

\Delta T_f = 1.86 \times 1.1 \times 1 = 2.046 ^{\circ}C

Therefore the freezing point will be 0 - 2.046°C = -2.046°C.

8 0
3 years ago
Balance the reaction of c6h12o6(s)+o2(g)=co2(g)+h2o(l)
avanturin [10]

6CO2 + 7H2O = C6H12O6 + 6O2 + H2O

Explanation:

CO2 + H2O = C6H12O6 + O2 + H2O

Starting carbon atoms,

1C on reactants and 6C on products,

therefore you should start by putting a 6 on CO2

6CO2 + H2O = C6H12O6 + O2 + H2O

Proceed with Hydrogen,

Reactants → 2H

Products → 14H

You should multiply H2O with 7 .

6CO2 + 7H2O = C6H12O6 + O2 + H2O

the we need to proceed for Oxygen,

Reactants → 12 + 7= 19O

Products → 6 O in C6H12O6, 2O in O2 and 1O in H2O

we need to balance the equation without disrupting the balance of other atoms, so we need to Multiply O2 with 6

The required balanced equation is  

6CO2 + 7H2O = C6H12O6 + 6O2 + H2O

3 0
4 years ago
What is chromatography?
Lunna [17]
The separation of a mixture by passing it in solution through a medium in which the components move at different rates

5 0
4 years ago
A certain substance X has a normal freezing point of −3.1°C and a molal freezing point depression constant =Kf·6.23°C·kgmol−1. C
muminat

Answer:

Freezing T° of solution =  - 7.35 °C

Explanation:

This is about the freezing point depression, a colligative property which depends on solute.

The formula is: Freezing T° pure solvent - Freezing T° solution = m . Kf . i

Freezing T° of pure solvent is -3.1°C

At this case, i = 1. As an organic compound the urea does not ionize.

We determine the molality (mol/kg of solvent)

We convert mass to moles:

12.3 g . 1mol / 60.06 g = 0.205 moles

0.205 mol / 0.3 kg = 0.682 mol/kg

We replace data in the formula:

-3.1°C - Freezing T° of solution  = 0.682 mol/kg . 6.23 kg°C/mol . 1

Freezing T° of solution = 0.682 mol/kg . 6.23 kg°C/mol . 1 + 3.1°C

Freezing T° of solution =  - 7.35 °C

6 0
4 years ago
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