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2 years ago

Does the absolute reference system consider a fixed reference system of reference?

Chemistry

1 answer:

Rufina [12.5K]2 years ago

6 0

Answer:

The definition of an absolute reference frame would be that fixed reference frame that every observer would rest at all times in his/her state of motion.

Explanation:

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5. Organisms that make their own energy storage molecules are called producers. What process do

Dominik [7]

Answer:

I think it's metabolism

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3 years ago

"Thermite" reactions have been used for welding metal parts such as railway rails and in metal refining. One such thermite react

frosja888 [35]

<u>Answer:</u> The given reaction is non-spontaneous in nature.

<u>Explanation:</u>

Entropy change is defined as the difference in entropy of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate entropy change is of a reaction is:

$\Delta S^o_{rxn}=\sum [n\times \Delta S^o_{(product)}]-\sum [n\times \Delta S^o_{(reactant)}]$

For the given chemical reaction:

$3Mg(s)+Cr_2O_3(s)\rightarrow 3MgO(s)+2Cr(s)$

The equation for the entropy change of the above reaction is:

$\Delta S^o_{rxn}=[(3\times \Delta S^o_{(MgO(s))})+(2\times \Delta S^o_{(Cr(s))})]-[(3\times \Delta S^o_{(Mg(s))})+(1\times \Delta S^o_{(Cr_2O_3(s))})]$

We are given:

$\Delta S^o_{(Mg(s))}=32.68J/K.mol\\\Delta S^o_{(Cr_2O_3(s))}=81.2J/K.mol\\\Delta S^o_{(MgO(s))}=26.94J/K.mol\\\Delta S^o_{(Cr(s))}=23.77J/K.mol$

Putting values in above equation, we get:

$\Delta S^o_{rxn}=[(3\times (26.94))+(2\times (23.77))]-[(3\times (32.68))+(1\times (81.2))]\\\\\Delta S^o_{rxn}=-50.88J/K=-0.0509kJ/K.mol$

For the reaction to be spontaneous, the Gibbs free energy of the reaction must come out to be negative.

To calculate the standard Gibbs free energy of the reaction, we use the equation:

$\Delta G^o=\Delta H^o-T\Delta S^o$

where,

$\Delta G^o$ = standard Gibbs free energy = ?

$\Delta H^o$ = standard enthalpy change of the reaction = 665.1 kJ/mol

T = Temperature = 298.15 K

$\Delta S^o$ = standard entropy change of the reaction = -0.0509 kJ/K.mol

Putting values in above equation, we get:

$\Delta G^o=(665.1kJ/mol)-(298.15K\times (-0.0509kJ/K.mol))=680.27kJ/mol$

As, the Gibbs free energy of the reaction is coming out to be positive, the reaction is non-spontaneous in nature.

Hence, the given reaction is non-spontaneous in nature.

4 0

4 years ago

How many kilograms of water form when 48 kg of oxygen gas chemically combine with 6 kg of hydrogen gas?

Snezhnost [94]

That would equal 54 kilograms of water. i know it sounds dumb but you have to realize that the weight will not just decrease since that's the units of measure were dealing with

6 0

4 years ago

What is the best description of the energy stored in a stretched or compressed object.

oksian1 [2.3K]

Answer:

Elastic Potential Energy

4 0

4 years ago

Please help. Last grade of this class

Marat540 [252]

Answer: Question 3

Group 14, Period 3 is a metalloid

Explanation: Question 3

The element in group 14, period 3 on the periodic table is Si. Metalloids are elements which share both non-metallic and metallic characteristics.

5 0

4 years ago