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2 years ago

WHICH ONE IS CORRECT???

Physics

2 answers:

sveta [45]2 years ago

5 0

Answer:

Explanation:

Julli [10]2 years ago

3 0

Answer:

According to Pascals law, THE PRESSURE EXERTED TO A CONFINED LIQUID IS TRANSMITTED EQUALLY AND UNDIMINISHED IN ALL DIRECTIONS THROUGHOUT THE MASS OF THE LIQUID--Blaise Pascal

so the pressure at A2 must be equal to A1

buy however the F1 will be less than F2 since:

P1=F1/A1 and P2=F2/F1

P1=P2 according to Pascal

so, F1/A1=F2/A2

with less amount of force at P1 THE force gets multiplied.

Therefore it's obvious that option A and B is wrong. I can't see option C properly.

but, you are going to have this option.

C.F1>F2

so the option with F1>F2 is correct

PLEASE MARK BRAINLIEST

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2 years ago

Suppose a large housefly 3.0 m away from you makes sound with an intensity level of 40.0 dB. What would be the sound intensity l

melisa1 [442]

Answer:

Explanation:

Let the intensity of the noise be represented by I

Given that

40dB = 10 log 10 ⁡ ( I /I•) ........ 1

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3 years ago

Give two examples from the fossil record that show evidence of change in the complexity of organisms over time.

polet [3.4K]

Answer:

Fossils tell us when organisms lived, as well as provide evidence for the progression and evolution of life on earth over millions of years.

Explanation:

As the world changes, plants and animals change with it. Aside from a few living fossils, the species we see today are very different from species that lived in the past. Thus, the fossil record can be used to show that organisms changed to meet new conditions. ... This is the result of evolution of species over time.

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2 years ago

A force of 6600 N is exerted on a piston that has an area of 0.010 m2

sveticcg [70]

Answer:

Choice A: approximately $0.015\; \rm m^2$ , assuming that the two pistons are connected via some confined liquid to form a simple machine.

Explanation:

Assume that the two pistons are connected via some liquid that is confined. Pressure from the first piston:

$\displaystyle P_1 = \frac{F_1}{A_1} = \frac{6.600\times 10^3\; \rm N}{1.0\times 10^{-2}\; \rm m^{2}} = 6.6\times 10^{5}\; \rm N \cdot m^{-2}$ .

By Pascal's Principle, because the first piston exerted a pressure of $6.6\times 10^{5}\; \rm N \cdot m^{-2}$ on the liquid, the liquid will now exert the same amount of pressure on the walls of the container.

Assume that the second piston is part of that wall. The pressure on the second piston will also be $6.6\times 10^{5}\; \rm N \cdot m^{-2}$ . In other words:

$P_2 = P_1 = 6.6\times 10^{5}\; \rm N \cdot m^{-2}$ .

To achieve a force of $9.900 \times 10^3\; \rm N$ , the surface area of the second piston should be:

$\displaystyle A_2 = \frac{F_2}{P_2} = \frac{9.900\times 10^{3}\; \rm N}{6.6\times 10^5\; \rm N \cdot m^{-2}} \approx 0.015\; \rm m^{2}$ .

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3 years ago