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Rzqust [24]
2 years ago
6

Please help! i will give brainliest :)

Physics
1 answer:
Sunny_sXe [5.5K]2 years ago
5 0

Answer:

im blind

Explanation:

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A 900 kg vehicle moves around a curve with an incline of 20\circ∘ at a speed of 12.5 m/s. If the curve has a radius of 50 meters
valentina_108 [34]

Answer:

The normal force experienced by the car is approximately 8223.2 N

Explanation:

The question relates to banking of road where the centripetal force for the circular motion of the vehicle is provided by the horizontal component of the normal reaction

The mass of the vehicle that moves around the curve, m = 900 kg

The incline of the curve, θ = 20°

The speed with which the vehicle moves around the curve, v = 12.5 m/s

The radius of the curve, R = 50 meters

We have;

N \cdot sin(\theta) = \dfrac{m \cdot v^2}{R}

Where;

θ = The angle of inclination of the road = 20°

N = The normal force experienced by the car

m = The mass of the car = 900 kg

v = The velocity with which the car is moving = 12.5 m/s

R = The radius of the curve around which the vehicle moves = 50 m

\therefore N = \dfrac{m \cdot v^2}{R \cdot sin(\theta)} = \dfrac{900 \times (12.5)^2}{50 \times sin(20^{\circ})}  = 8223.1998754586828969046217875927

The normal force experienced by the car = N ≈ 8223.2 N.

6 0
2 years ago
airplane in flight has a pressure difference between the lower and upper wing surface; this provides an upward force that balanc
Dvinal [7]

Answer:

4523.17365 Pa

Explanation:

m = Mass of plane = 77000 kg

F = Force = Weight = mg

g = Acceleration due to gravity = 9.81 m/s²

A = Total area of wings = 167 m²

The pressure difference would be

\Delta P=\dfrac{F}{A}\\\Rightarrow \Delta P=\dfrac{77000\times 9.81}{167}\\\Rightarrow \Delta P=4523.17365\ Pa

The pressure difference required to keep the plane aloft is 4523.17365 Pa

3 0
3 years ago
What is an object's change in position, or displacement, and the change in time over which that displacement occurred used to ca
nikklg [1K]
The average velocity as velocity is equal to displacement/time
7 0
3 years ago
A ball is launched with initial speed v from the ground level up a frictionless hill. the hill becomes steeper as the ball slide
frutty [35]
<span>if we take ball then the Kinetic Energy of the ball is ½mV² as it rolls up the slope, the Kinetic Energy is converted to potential energy, PE = mgh. mgh = ½mV² h = V²/2g</span>
4 0
3 years ago
Read 2 more answers
A duck has a mass of 2.70 kg. As the duck paddles, a force of 0.110 N acts on it in a direction due east. In addition, the curre
Maurinko [17]

a) The magnitude will be 0.838m

b) The displacement will be -17.35°

<h3>What is displacement?</h3>

The path covered by an object from its initial point to final point.

Forces acting on the duck

x-axis:    0.13 + 0.16*cos(-56°) = 2.7 * ax  

ax = 0.0813 m/s^2

y-axis:    0.13*sin(-56°) = 2.7 * ay  

ay = -0.0491 m/s^2

The displacement on the x-axis

X = Vox * t + ax/2 * t²

X = 0.12* 3.2 + 0.0813/2*3.2²

X = 0.8

The displacement on the y-axis:

Y = Voy * t + ay/2 * t²

X = 0 - 0.0491/2*3.2²

Y=-0.25m

So, the magnitude and angle of this displacement [0.8,-0.25] is:

0.838m  at an angle of -17.35°

For more displacement related question visit

brainly.com/question/11934397

#SPJ1

7 0
2 years ago
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