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2 years ago

7. Justify why these ions do not exist under normal conditions. (a) K2+ (b) 0-

1 answer:

6 0

K^+ can not exists because electrons are removed from an inner shell. The ion O^- can not exist because it will have an incomplete octet.

<h3>Stability of ions</h3>

Ions are species that contain a positive or a negative charge. When we consider the electron configuration of ions, we can deduce the stability of the ion.

Let us consider the electron configuration of K^2+ which is 1s2 2s2 2p6 3s2 3p5 which means that the second electron is to be removed from an inner shell which implies greater energy expenditure hence it does not exist.

In the case of O^-, involves the formation of an ion with an incomplete octet which is not possible.

Learn more about ions: brainly.com/question/1782326

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Answer:

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3 years ago

Which of the following does not correctly describe Sn2 reactions of alkyl halides? A) The mechanism consists of a single step wi

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Answer:

The correct answer is B the tertiary halides reacts faster than primary halides.

Explanation:

During SN2 reaction the nucleophile attack the alkyl halide from the opposite side resulting in the formation of transition state in which a bond is not completely broken or a new bond is not completely formed.

After a certain period of time the nucleophile attach with the substrate by substituting the existing nuclophile.

An increase in the bulkiness in the alkyl halide the SN2 reaction rate of that alkyl halide decreases.This phenomenon is called steric hindrance.

So from that point of view the that statement tertiary halides reacts faster that secondary halide is not correct.

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3 years ago

5. What is the final "Celsius" temperature if 2.40 L of gas at 30.5 C is cooled until the volume reaches 1.00 L at constant pres

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Answer:

Final temperature of the gas = -146.63 °C

Explanation:

At constant pressure, volume and temperature of the gases are related as:

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

Where,

V1 = Initial volume = 1.00 L

V2 = Final volume = 2.40 L

T1 = Initial temperature = 30.5 °C = 30.5 + 273.15 = 303.65 K

Now, substitute the values in the above equation,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

$\frac{2.40\;L}{303.65}=\frac{1.00\;L}{T_2}$

$T_2=\frac{1.00\times 303.65}{2.40}$

T2 = 126.52 K

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

T( °C) = T(K) - 273.15

= 126.52 - 273.15 = -146.63 °C

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3 years ago

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When a substance melts, the solid gains heat, and the motion of the particles increases (particles move faster in liquid form than in solid form).

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