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adoni [48]
2 years ago
10

7. Justify why these ions do not exist under normal conditions. (a) K2+ (b) 0-

Chemistry
1 answer:
ladessa [460]2 years ago
6 0

K^+ can not exists because electrons are removed from an inner shell. The ion O^- can not exist because it will have an incomplete octet.

<h3>Stability of ions</h3>

Ions are species that contain a positive or a negative charge. When we consider the electron configuration of ions, we can deduce the stability of the ion.

Let us consider the electron configuration of K^2+ which is 1s2 2s2 2p6 3s2 3p5 which means that the second electron is to be removed from an inner shell which implies greater energy expenditure hence it does not exist.

In the case of O^-, involves the formation of an ion with an incomplete octet which is not possible.

Learn more about ions: brainly.com/question/1782326

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4.) an element cannot be decomposed by a chemical change, it is a pure substance and no other materials compose it.
3 0
4 years ago
Calculate the decrease in temperarure when 2.00 L at 20.0 degrees celsius is compressed to 1.00 L.
Serga [27]
I suspect that the pressure of this change is constant therefore

The equation is used from the combined gas law. (When pressure is constant both P's will cancel out P/P = 1)
V/T = V/T
Initial   Change

Initially we have 2L at 20 degress what temperature will be at 1L.

2/20 = 1/T
0.1 = 1/T
0.1T = 1
T = 1/0.1
T = 10 degress celsius.

Hope this helps if you won't be able to understand what is the combined gas law just tell me :).
3 0
3 years ago
Does the amount of a substance affect the properties of a substance?
Veseljchak [2.6K]
No, the properties of a substance are not affected by the amount of a substance.
5 0
3 years ago
When the glucose transport maximum is reached, _______.?
n200080 [17]
Glucose is extracted in the urine and all of the glucose is reabsorbed. 
8 0
3 years ago
Determine the poh of a 0.348 m ba(oh)2 solution at 25°c.
vladimir1956 [14]

<u>Given:</u>

Concentration of Ba(OH)2 = 0.348 M

<u>To determine:</u>

pOH of the above solution

<u>Explanation:</u>

Based on the stoichiometry-

1 mole of Ba(OH)2 is composed of 1 mole of Ba2+ ion and 2 moles of OH- ion

Therefore, concentration of OH- ion = 2*0.348 = 0.696 M

pOH = -log[OH-] = - log[0.696] = 0.157

Ans: pOH of 0.348M Ba(OH)2 is 0.157

6 0
4 years ago
Read 2 more answers
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