Question

A person is running at an initial velocity of 3.7 m/s. If the person is accelerating at 2 m/s2, what is their final velocity after 3 seconds?

Answer 1

Answer:

9.7m/s

Explanation:

$\pink{\frak{Given}}\begin{cases} \textsf{ Initial velocity of a person is 3.7m/s .}\\\textsf{The acceleration of the person is 2m/s ^2 .} \end{cases}$

And we need to find out the velocity of the person after 3 seconds . Here we can use the First equation of motion namely ,

$\sf \longrightarrow v = u + at$

Where ,

• v is the final velocity .
• u is the initial velocity .
• a is the acceleration .
• t is the time taken .

Now substitute the respective values in the given equation ,

$\sf \longrightarrow v = 3.7m/s + 2m/s^2*3s$

Simplify ,

$\sf \longrightarrow v = 3.7m/s + 6m/s$

$\sf \longrightarrow \boxed{\bf velocity_{After\ 3 \ s }= 9.7 m/s}$

Hence the velocity after 3 seconds is 9.7 m/s .

Answer 2

Answer:

9.7 ms⁻¹

Explanation:

The formula to find the acceleration is :

$Acceleration=\frac{Final \:Velocity-Initial\:Velocity}{Time}$

According to the question, we are asked to find the Final Velocity.

For that, let the Final Velocity be x.

$Acceleration=\frac{Final \:Velocity-Initial\:Velocity}{Time}$

$2m/s^{2} =\frac{x-3.7m/s}{3 s}$

$2 =\frac{x-3.7}{3 }$

$2*3=x-3.7$

$6=x-3.7$

$6+3.7=x$

$9.7=x$

Therefore,

Final velocity = 9.7ms⁻¹

Hope this helps you :-)

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