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3 years ago

As liquid water freezes, what happens to its thermal energy?

Physics

2 answers:

Andrew [12]3 years ago

6 0

Answer:

Explanation:

Shtirlitz [24]3 years ago

4 0

Answer:

I believe it is C

Explanation:

When the water freezes the kinetic energy decreases because it is staying in place instead of moving around, which also causes thermal energy to decrease.

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Two cars are lifted to the same elevation in a service station. If one car is twice as massive as the other, how do their potent

Ymorist [56]

Answer:

1. The car which is twice as massive as the other will have twice potential energy.

Explanation:

The potential energy of an object is given by:

$U=mgh$

where

m is the mass of the object

g is the gravitational acceleration

h is the height of the object measured to some reference level

In this problem, we have two cars at same elevation (= same h in the formula) but one car has twice the mass of the second car. Calling m the mass of one car and 2m the mass of the second car, we have:

- Potential energy of the first car:

$U=mgh$

- potential energy of the second car:

$U'=(2m)gh=2mgh=2U$

So, the car which is twice as massive as the other will have twice potential energy.

3 0

4 years ago

Two particles having charges of 0.440 nC and 11.0 nC are separated by a distance of 1.80 m . 1) At what point along the line con

Harlamova29_29 [7]

Answer:

a) 0.3 m

b) r = 0.45 m

Explanation:

given,

q₁ = 0.44 n C and q₂ = 11.0 n C

assume the distance be r from q₁ where the electric field is zero.

distance of point from q₂ be equal to 1.8 -r

now,

E₁ = E₂

$\dfrac{K q_2}{(1.8-r)^2} = \dfrac{K q_1}{r^2}$

$(\dfrac{1.8-r}{r})^2= \dfrac{q_2}{q_1}$

$\dfrac{1.8-r}{r}= \sqrt{\dfrac{11}{0.44}}$

1.8 = 6 r

r = 0.3 m

<h3>b) zero when one charge is negative.</h3>

let us assume q₁ be negative so, distance from q₁ be r

from charge q₂ the distance of the point be 1.8 +r

now,

E₁ = E₂

$\dfrac{K q_2}{(1.8+r)^2} = \dfrac{K q_1}{r^2}$

$(\dfrac{1.8+r}{r})^2= \dfrac{q_2}{q_1}$

$\dfrac{1.8+r}{r}= \sqrt{\dfrac{11}{0.44}}$

1.8 =4 r

r = 0.45 m

4 0

4 years ago

Consider a plastic rod that is being charged up by rubbing a wool cloth. It is then brought to an initially neutral metallic sph

anygoal [31]

Answer:

A) is repelled by the sphere

Explanation:

When a piece of plastic is rubbed with a wooden cloth, it sinks negatively
Let it change Q. So it is now allowed to touch the neutral zone. Therefore, there is a difference in the surface capacity of the two bodies, so that charge transfer takes place
Some of its negative charge is transferred to the metal sphere, now both the rod and the sphere are negatively charged and the same chargers as we know are repelled by each other.
so correct answer is A) is repelled by sphere

7 0

3 years ago

WILL GIVE BRAINLIEST!!!

kumpel [21]

Answer:

72.53 mi/hr

Explanation:

From the question given above, the following data were obtained:

Vertical distance i.e Height (h) = 8.26 m

Horizontal distance (s) = 42.1 m

Horizontal velocity (u) =?

Next, we shall determine the time taken for the car to get to the ground.

This can be obtained as follow:

Height (h) = 8.26 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

h = ½gt²

8.26 = ½ × 9.8 × t²

8.26 = 4.9 × t²

Divide both side by 4.9

t² = 8.26 / 4.9

Take the square root of both side by

t = √(8.26 / 4.9)

t = 1.3 s

Next, we shall determine the horizontal velocity of the car. This can be obtained as follow:

Horizontal distance (s) = 42.1 m

Time (t) = 1.3 s

Horizontal velocity (u) =?

s = ut

42.1 = u × 1.3

Divide both side by 1.3

u = 42.1 / 1.3

u = 32.38 m/s

Finally, we shall convert 32.38 m/s to miles per hour (mi/hr). This can be obtained as follow:

1 m/s = 2.24 mi/hr

Therefore,

32.38 m/s = 32.38 m/s × 2.24 mi/hr / 1 m/s

32.38 m/s = 72.53 mi/hr

Thus, the car was moving at a speed of

72.53 mi/hr.

7 0

3 years ago

Esercizio 1

timama [110]

Explanation:

can u please translate it to english language. I can't understand.

7 0

3 years ago