We are given with a compound, Lithium (Li) having a 4.8x 10 ^24 atoms. We are tasked to solve for it's corresponding grams.Note that 1 mol=6.022x10^{23} atoms and Li has 6.94 g/mol, hence,g Li= 4.8x 10 ^24 atoms x 1 mol/6.022x10^{23} atoms x 6.94 g Li/1mol Li=
55.32 g
Therefore, the grams of Lithium is 55.32 g.
Answer:
5.58x1023Agatoms 5.58 x 10 23 A g a t o m s
Explanation:
After determining the moles of the sample, we can convert it to the number of atoms using the Avogadro's number.
<u>Answer:</u> The cell potential of the above reaction is 0.52 V
<u>Explanation:</u>
The given chemical equation follows:

<u>Oxidation half reaction:</u> 
<u>Reduction half reaction:</u> 
To calculate the EMF of the cell, we use the Nernst equation, which is:
![E_{cell}=E^o_{cell}-\frac{0.059}{n}\log \frac{[Zn^{2+}]}{[Pb^{2+}]}](https://tex.z-dn.net/?f=E_%7Bcell%7D%3DE%5Eo_%7Bcell%7D-%5Cfrac%7B0.059%7D%7Bn%7D%5Clog%20%5Cfrac%7B%5BZn%5E%7B2%2B%7D%5D%7D%7B%5BPb%5E%7B2%2B%7D%5D%7D)
where,
= electrode potential of the cell = ? V
= standard electrode potential of the cell = 0.63 V
n = number of electrons exchanged = 2
![[Zn^{2+}]=1.0M](https://tex.z-dn.net/?f=%5BZn%5E%7B2%2B%7D%5D%3D1.0M)
![[Pb^{2+}]=2.0\times 10^{-4}M](https://tex.z-dn.net/?f=%5BPb%5E%7B2%2B%7D%5D%3D2.0%5Ctimes%2010%5E%7B-4%7DM)
Putting values in above equation, we get:

Hence, the cell potential of the above reaction is 0.52 V
Things expand when heated. therefore the molecules are farther apartand the matierial is less dense. Things expand because their molecules are vibrating faster and are taking up more space