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3 years ago

What type of bonding occurs in potassium oxide, k2o?

Chemistry

1 answer:

Naya [18.7K]3 years ago

6 0

Would be considered as an iconic bond.

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How many atoms are in 19.6 g of Sodium?

Hitman42 [59]

Answer:

Number of atoms = 5.1345 x 10²³

Explanation:

Given:

Mass of sodium = 19.6

Find:

Number of atoms

Computation:

We know that atomic mass of sodium is 22.98

So,

Number of atoms = [Mass of sodium/atomic mass of sodium]Avogadro's number

Number of atoms = [19.6 / 22.98]6.02 x 10²³

Number of atoms = 5.1345 x 10²³

can i have Brainliest i need 1 more

7 0

3 years ago

PLEASE HELP What's the mass in grams of 0.442 moles of calcium bromide, CaBr2? The atomic

djverab [1.8K]

Answer: Thus there are 88.4 g of calcium bromide.

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number $6.023\times 10^{23}$ of particles.

Molar mass of = 40.1 (1)+ 2(79.9) = 199.9

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

$0.442=\frac{x}{199.9}$

$x=88.4g$

Thus there are 88.4 g of calcium bromide.

7 0

3 years ago

Please help me!!!!!!!!

Semmy [17]

Surface runoff, its quite obvious in the picture

3 0

3 years ago

Ions can have a positive or negative charge. false or true

Fudgin [204]

True. Ions can have a positive or negative charge.

7 0

3 years ago

Read 2 more answers

To test the effectiveness of a gunpowder mixture, 1 gram was exploded under controlled STP conditions, and the reaction chamber

Alekssandra [29.7K]

Answer:

1.3 × 10³ cm³

Explanation:

The gas occupies a volume of V₁ = 310 cm³ under standard temperature and pressure (STP), that is, T₁ = 273.15 K and P₁ = 1.0 atm. In order to find the volume V₂ under different conditions we can use the combined gas law formula.

$\frac{P_{1}.V_{1}}{T_{1}} =\frac{P_{2}.V_{2}}{T_{2}} \\V_{2}=\frac{P_{1}.V_{1}.T_{2}}{T_{1}.P_{2}}=\frac{1.0atm\times 310cm^{3} \times 2473K }{273.15K \times 2.1atm} =1.3 \times 10^{3} cm^{3}$

7 0

3 years ago