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Karo-lina-s [1.5K]

2 years ago

12

If you are at latitude 43 degrees north of Earth's equator, what is the angular distance (in degrees) from your zenith to the no

rth celestial pole?

1 answer:

kirill115 [55]2 years ago

8 0

Answer:

Your zenith is 43 N of 90 deg (equator)

Thus, your zenith is 90 - 43 = 47 deg

(At the N pole your zenith would be 0 deg from the N pole)

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An organ pipe open at both ends has two successive harmonics with frequencies of 220 Hz and 240 Hz. What is the length of the pi

Harman [31]

Answer:

The length is $l = 8.6 \ m$

Explanation:

From the question we are told that

The frequencies of the two successive harmonics are $f_1 = 220 \ Hz$ , $f_2 = 240 \ Hz$

The speed of sound in the air is $v_s = 343 \ m/s$

Generally the frequency of a given harmonic is mathematically represented as

$f_n = \frac{n v }{2l}$

Here n defines the position of the harmonics

Now since the position of both harmonic is not know but we know that they successive then we can represented them mathematically as

$220 = \frac{n v}{2l}$

and

$240 = \frac{(n+1) v}{2l}$

So

$\frac{(n + 1 ) v}{2l} - \frac{n v}{2l} = 240-220$

=> $\frac{v}{2l} = 20$

=> $l = 8.6 \ m$

7 0

3 years ago

A certain car engine delivers enough force to create 630 N⋅m of torque when the engine is operating at 3200 revolutions per minu

jekas [21]

The appropriate expression for the calculation of power by relating the angular energy in a given time.

In other words the instantaneous power of an angular accelerating body is the torque times the angular velocity

$P=\tau\omega$

Where

$\tau =$ Torque

$\omega =$ Angular speed

Our values are given by

$\tau = 630Nm$

$\omega = 3200rev/min$

The angular velocity must be transformed into radians per second then

$\omega = 3200rev/min (\frac{2\pi rad}{60s})$

$\omega = 335.103rad/s$

Replacing,

$P=(630)(335.103)$

$P = 211.11*10^3W$

$P = 211.1kW$

The average power delivered by the engine at this rotation rate is 211.1kW

5 0

3 years ago

The sound level measured in a room by a person watching a movie on a home theater system varies from 40 dB during a quiet part t

UNO [17]

Answer:

$\alpha=-3.01dB$

Explanation:

From the question we are told that:

Sound level intensity

$\triangle I=40dB-80dB$

Generally the equation for intensity level is mathematically given by

$\alpha=10log_{10}(I/I_x)dB$

Where

I= Intensity measured

$I_x=Threshold\ of\ audibility$

$I_x= 10-12 W / m2$

$\alpha= 10 log10 \frac{I_1}{I_x} - 10 log10 \frac{}I_2{I_x}$

$\alpha= 10 log10 \frac{I_1}{I_2}$

$\alpha=10 log10\frac{40}{80}$

$\alpha=-3.01dB$

7 0

3 years ago

1. If a fast-moving car making a loud noise approaches and moves past the person, what will happen as the distance between the t

PilotLPTM [1.2K]

<span>So we want to know what will happen when the fast moving car that is making loud noise that is initially approaching the person, passes the person and starts to move away. So Doppler effect is a phenomenon where when the source of a sound is approaching a person, the person hears the sound as higher than if the source was standing still with respect to the person because the wavelength is getting shorter, and as the source is moving avay from the person the sound is getting deeper because the wavelength is getting longer. So the correct answer is A. </span>

4 0

3 years ago

Read 2 more answers

Inertia is the resistance to change in motion so inertia depends solely on what

Alex Ar [27]

Inertia depends on mass, the more mass the more inertia.

6 0

3 years ago