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Karo-lina-s [1.5K]

2 years ago

12

If you are at latitude 43 degrees north of Earth's equator, what is the angular distance (in degrees) from your zenith to the no

rth celestial pole?

1 answer:

kirill115 [55]2 years ago

8 0

Answer:

Your zenith is 43 N of 90 deg (equator)

Thus, your zenith is 90 - 43 = 47 deg

(At the N pole your zenith would be 0 deg from the N pole)

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What did nicolaus copernicus discover about the universe

Keith_Richards [23]

Answer:

Copernicus discoveres thr heliocentric theory. It was previously believed that everything orbited the Earth, geocentric theory. Copernicus said he believed the Earth and everything else orbited around the Sun.

8 0

3 years ago

A 500N person stands 2.5m from a wall against which a horizontal beam is attached. The beam is 6m long and weighs 200N. A cable

Vinil7 [7]

PART A)

Here by force balance along Y direction

$Tsin45 + F_y = 500 + 200$

Force balance along X direction

$Tcos45 = F_x$

now by torque balance

$Tsin45 (6) = 500 (2.5) + 200 (3)$

$T(4.24) = 1250 + 600$

$T = 436.3 N$

PART B)

now from above equations

$Tsin45 + F_y = 700$

$F_y = 391.5 N$

$F_x = Tcos45 = 308.5 N$

now net reaction force of wall is given as

$F = \sqrt{F_x^2 + F_y^2}$

$F = 498.4 N$

5 0

2 years ago

Why a boat cannot be made of solid steel.

Tju [1.3M]

Answer:

You want it to sink?

Of course u dont want to

5 0

3 years ago

Read 2 more answers

a block of wood with a mass of 2.33 kg is at rest on a frictionless pole. A .011 kg bullet is fired 722 m/s and is embedded with

MrRissso [65]

Some rewards are 2.33 miles in a hour so you have to move in 700 degrees to get the system moving faster soo 700+ 2.33 divide by 3

6 0

2 years ago

an elevator mass of 7700 kg falls from a height of 32 m after a sudden failure in the hoisting cable. The mass is stopped by a s

valkas [14]

Answer:k=28.29 kN/m

Explanation:

Given

mass $m =7700 kg$

height from which Elevator falls $h=32 m$

Let x be the compression in the spring

thus From conservation of Energy Potential energy will convert in to Elastic Potential Energy of spring

$\frac{kx^2}{2}=mg(h+x)$ ----------1

also maximum acceleration is 5g

thus

$mg-kx=ma$

here $a=-5g$

$kx=mg-m(-5g)=6mg$

$x=\frac{6mg}{k}$

Substitute x in equation 1

$0.5\times k\times (\frac{6mg}{k})^2=mg(h+\frac{6mg}{k})$

$18\frac{(mg)^2}{k}=mgh+6\frac{(mg)^2}{k}$

$k=12\cdot \frac{mg}{h}$

$k=12\times \frac{7700\times 9.8}{32}$

$k=28.29 kN/m$

4 0

2 years ago