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Karo-lina-s [1.5K]

2 years ago

12

If you are at latitude 43 degrees north of Earth's equator, what is the angular distance (in degrees) from your zenith to the no

rth celestial pole?

1 answer:

kirill115 [55]2 years ago

8 0

Answer:

Your zenith is 43 N of 90 deg (equator)

Thus, your zenith is 90 - 43 = 47 deg

(At the N pole your zenith would be 0 deg from the N pole)

You might be interested in

ExtremeBDS [4]

Answer:

Just as the angles of the sun, moon and Earth affect tidal heights over the course of a lunar month, so do their distances to one another. Because the moon follows an elliptical path around the Earth, the distance between them varies by about 31,000 miles over the course of a month.

Hope this helped, have a nice rest of your day!

3 0

3 years ago

Steam enters a turbine at 400K and exhausts at 360K. Calculate the maximum efficiency. =%

kozerog [31]

The maximum efficiency is 10%

Explanation:

The maximum efficiency of a machine is given by:

$\eta=1-\frac{T_C}{T_H}$

where

$T_H$ is the temperature of the hot reservoir

$T_C$ is the temperature of the cold reservoir

For the machine in this problem, we have:

$T_H=400K$ is the temperature of the hot reservoir

$T_C=360K$ is the temperature of the cold reservoir

substituting, we find the max efficiency:

$\eta=1-\frac{360}{400}=0.1$

So, the efficiency is 0.10 (10%).

Learn more about temperature:

brainly.com/question/1603430

brainly.com/question/4370740

#LearnwithBrainly

8 0

3 years ago

A cannon sits on the edge of a castle wall that is 15 m above the ground. A cannon ball leaves the cannon with an initial veloci

Juli2301 [7.4K]

Answer:

a

Explanation:

4 0

3 years ago

The age of a piece of wood from an archeological site is to be determined using the Carbon-14 method. The activity of the sample

Bond [772]

Answer:

4276.98 years

Explanation:

t = age of the sample in numbers of years

T = half life of the carbon-14 isotope = 5730 yrs

λ = decay constant of carbon-14

decay constant is given as

$\lambda =\frac{0.693}{T}$

$\lambda =\frac{0.693}{5730}$

$\lambda = 0.000121$

A₀ = activity of Carbon-14 in living plants

A = activity of Carbon-14 after time "t" = (0.596) A₀

Using the equation

$A = A_{o} e^{-\lambda t}$

$(0.596) A₀ = A_{o} e^{-0.000121 t}$

$0.596 = e^{-0.000121 t}$

t = 4276.98 years

4 0

3 years ago

A bullet of mass 0.107 kg traveling horizontally at a speed of 300 m/s embeds itself in a block of mass 3 kg that is sitting at

melisa1 [442]

Answer:

165.77J

Explanation:

M₁ = 0.107kg

u₁ = 300m/s

m₂ = 3kg

u₂ = 0

v =

m₁u₁ + m₂u₂ = (m₁ + m₂)V

(0.107*300) + 0 = (0.107 + 3)V

V = 32.1 / 3.107 = 10.33m/s

kinetic energy of the system after collision =

½m1v² + ½m2v²

K.E = ½(m1 + m2)v²

K.E = ½(0.107+3) * 10.33²

K.E = 165.77J

5 0

3 years ago