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vredina [299]
2 years ago
13

40

Chemistry
1 answer:
kap26 [50]2 years ago
8 0

Answer:

what you've asked so I guess the answer will be 10 days

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Sodium nitrate and lead (ii) acetate express your answer as a chemical equation. identify all of the phases in your answer. ente
ICE Princess25 [194]

Answer: 2NaNO_3(aq)+(CH_3COO)_2Pb(aq)\rightarrow 2CH_3COONa(aq)+Pb(NO_3)_2(aq)

Explanation: A double displacement reaction is one in which exchange of ions take place.

The compounds which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.

Thus the exchange of ions take place and all the compounds are soluble so the chemical formulas are followed by the symbol (aq).

3 0
3 years ago
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According to our textbook, write the formula for the anhydrous compound that was part of the mixture called natron that was used
bearhunter [10]

Answer:

The formula for the anhydrous compound that was part of the mixture called natron that was used by the Egyptians is Na2(CO3)10(H2O).

They use this compound for medicine, cookery, agriculture, in glass-making and to dehydrate egyptian mummies.

Compound of sodium carbonate and sodium bicarbonate was the name of the resulting hydrate that formed.

8 0
2 years ago
Balanced equation for the neutralization of these 2. HCl , Ca(OH)2
Ghella [55]
Balanced equation:

<span>2 HCl + 1 Ca(OH)</span>₂<span> = 1 CaCl</span>₂<span> + 2 H</span>₂<span>O
</span>
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5 0
2 years ago
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2 years ago
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The rate constant for a certain reaction is k = 5.40×10−3 s−1 . If the initial reactant concentration was 0.100 M, what will the
IceJOKER [234]

Answer : The concentration after 17.0 minutes will be, 4.05\times 10^{-4}M

Explanation :

The expression for first order reaction is:

[C_t]=[C_o]e^{-kt}

where,

[C_t] = concentration at time 't'  (final) = ?

[C_o] = concentration at time '0' (initial) = 0.100 M

k = rate constant = 5.40\times 10^{-3}s^{-1}

t = time = 17.0 min = 1020 s (1 min = 60 s)

Now put all the given values in the above expression, we get:

[C_t]=(0.100)\times e^{-(5.40\times 10^{-3})\times (1020)}

[C_t]=4.05\times 10^{-4}M

Thus, the concentration after 17.0 minutes will be, 4.05\times 10^{-4}M

4 0
2 years ago
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