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Leya [2.2K]
2 years ago
13

Describe about simple cell. with well label diagram.​

Physics
1 answer:
dedylja [7]2 years ago
8 0

A simple electric has two terminals i.e. negative and positive, And it has a top and a bottom namely Metal Cap and Metal disc.

\red{ \rule{35pt}{2pt}} \orange{ \rule{35pt}{2pt}} \color{yellow}{ \rule{35pt} {2pt}} \green{ \rule{35pt} {2pt}} \blue{ \rule{35pt} {2pt}} \purple{ \rule{35pt} {2pt}}

<h3><u>Description of each part :-</u></h3>

  • <u>Metal</u><u> </u><u>cap</u><u>:</u><u>-</u><u> </u><em>The</em><em> </em><em>part</em><em> </em><em>which</em><em> </em><em>is</em><em> </em><em>above</em><em> </em><em>the</em><em> </em><em>positive</em><em> </em><em>terminal</em><em>,</em><em> </em><em>a</em><em> </em><em>cap</em><em> </em><em>of</em><em> </em><em>metal</em><em> </em><em>through</em><em> </em><em>which</em><em> </em><em>the</em><em> </em><em>positively</em><em> </em><em>charged</em><em> </em><em>electrons</em><em> </em><em>are</em><em> </em><em>passed</em><em>.</em>
  • <u>Metal</u><u> </u><u>disc</u><u>:</u><u>-</u><u> </u><em>The part which is </em><em>below</em><em> the </em><em>negative</em><em> terminal, a </em><em>disc</em><em> of metal through which the </em><em>negatively</em><em> </em><em>charged</em><em> electrons are passed.</em>
  • <u>Positive</u><u> </u><u>terminal</u><u>:</u><u>-</u><u> </u><em>In</em><em> </em><em>a</em><em> </em><em>circuit</em><em> </em><em>the</em><em> </em><em>current</em><em> </em><em>flows</em><em> </em><em>from</em><em> </em><em>positive</em><em> </em><em>terminal</em><em> </em><em>to</em><em> </em><em>negative</em><em> </em><em>terminal</em><em>.</em><em> </em>
  • These terminals are also known as cathode and anode.
  • Cathode is the other name for positive terminal and anode is the other name for negative terminal.

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Answer:

Hmax=15.06 meters

Explanation:The question ask for the maximum value of the function f(t) which can be find by find the maxima of the function

The maxima of the function occurs when the slope is zero. i.e.

\frac{df}{dt} =0\\\frac{df}{dt} =\frac{d}{dt} (-4.9t^2+16t+2)\\\frac{df}{dt} =-4.9*2t+16\\-9.8t+16=0\\t=16/9.8\\t=1.63 secs

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