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Leya [2.2K]
2 years ago
13

Describe about simple cell. with well label diagram.​

Physics
1 answer:
dedylja [7]2 years ago
8 0

A simple electric has two terminals i.e. negative and positive, And it has a top and a bottom namely Metal Cap and Metal disc.

\red{ \rule{35pt}{2pt}} \orange{ \rule{35pt}{2pt}} \color{yellow}{ \rule{35pt} {2pt}} \green{ \rule{35pt} {2pt}} \blue{ \rule{35pt} {2pt}} \purple{ \rule{35pt} {2pt}}

<h3><u>Description of each part :-</u></h3>

  • <u>Metal</u><u> </u><u>cap</u><u>:</u><u>-</u><u> </u><em>The</em><em> </em><em>part</em><em> </em><em>which</em><em> </em><em>is</em><em> </em><em>above</em><em> </em><em>the</em><em> </em><em>positive</em><em> </em><em>terminal</em><em>,</em><em> </em><em>a</em><em> </em><em>cap</em><em> </em><em>of</em><em> </em><em>metal</em><em> </em><em>through</em><em> </em><em>which</em><em> </em><em>the</em><em> </em><em>positively</em><em> </em><em>charged</em><em> </em><em>electrons</em><em> </em><em>are</em><em> </em><em>passed</em><em>.</em>
  • <u>Metal</u><u> </u><u>disc</u><u>:</u><u>-</u><u> </u><em>The part which is </em><em>below</em><em> the </em><em>negative</em><em> terminal, a </em><em>disc</em><em> of metal through which the </em><em>negatively</em><em> </em><em>charged</em><em> electrons are passed.</em>
  • <u>Positive</u><u> </u><u>terminal</u><u>:</u><u>-</u><u> </u><em>In</em><em> </em><em>a</em><em> </em><em>circuit</em><em> </em><em>the</em><em> </em><em>current</em><em> </em><em>flows</em><em> </em><em>from</em><em> </em><em>positive</em><em> </em><em>terminal</em><em> </em><em>to</em><em> </em><em>negative</em><em> </em><em>terminal</em><em>.</em><em> </em>
  • These terminals are also known as cathode and anode.
  • Cathode is the other name for positive terminal and anode is the other name for negative terminal.

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Answer:

H = 10.05 m

Explanation:

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\Delta t = 4.1 - 0.5 = 3.6 s

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now we have

v_f - v_i = at

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PLEASE HELP !!!
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A 25.0-kg child is standing at the edge of a horizontal merry-go-round with a radius of 2.40 m and a moment of inertia of 356 kg
motikmotik

Answer:

\omega_{f}=1.634\ rad/s  

Explanation:

given,  

diameter of merry - go - round = 2.40 m  

moment of inertia = I = 356 kg∙m²

speed of the merry- go-round = 1.80 rad/s

mass of child = 25 kg  

initial angular momentum of the system  

L_i = I\omega_i  

L_i =356\times 1.80  

L_i =640.8\ kg.m^2/s  

final angular momentum of the system  

L_f = (I_{disk}+mR^2)\omega_{f}  

L_f = (356 + 25\times 1.2^2)\omega_{f}  

L_f= (392)\omega_{f}  

from conservation of angular momentum  

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640.8= (392)\omega_{f}  

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