The average rate of reaction over a given interval can be calculated by taking the difference of concentration on a particular given reactant, and dividing it by the total time. In this case, (1.00 M - 0.655 M)/30 s = 0.0115 M/s, or 0.0115 mol/L-s, and this is the final rate of reaction.
Answer:
We mostly use Kilograms and grams to measure mass =)
Explanation:
We can set up an ICE table for the reaction:
HClO H+ ClO-
Initial 0.0375 0 0
Change -x +x +x
Equilibrium 0.0375-x x x
We calculate [H+] from Ka:
Ka = 3.0x10^-8 = [H+][ClO-]/[HClO] = (x)(x)/(0.0375-x)
Approximating that x is negligible compared to 0.0375 simplifies the equation to
3.0x10^-8 = (x)(x)/0.0375
3.0x10^-8 = x2/0.0375
x2 = (3.0x10^-8)(0.0375) = 1.125x10^-9
x = sqrt(1.125x10^-9) = 0.0000335 = 3.35x10^-5 = [H+]
in which 0.0000335 is indeed negligible compared to 0.0375.
We can now calculate pH:
pH = -log [H+] = - log (3.35 x 10^-5) = 4.47
<u>Answer:</u> The mass of sulfuric acid present in 60 mL of solution is 34.1 grams
<u>Explanation:</u>
We are given:
44 % (m/m) solution of sulfuric acid. This means that 44 grams of sulfuric acid is present in 100 grams of solution.
To calculate volume of a substance, we use the equation:
Density of solution = 1.343 g/mL
Mass of solution = 100 g
Putting values in above equation, we get:
To calculate the mass of sulfuric acid present in 60 mL of solution, we use unitary method:
In 77.46 mL of solution, mass of sulfuric acid present is 44 g
So, in 60 mL of solution, mass of sulfuric acid present will be = 
Hence, the mass of sulfuric acid present in 60 mL of solution is 34.1 grams
