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Ronch [10]
3 years ago
7

When would it be useful for gas to form?

Chemistry
2 answers:
Alexus [3.1K]3 years ago
8 0

Answer: A gas is a form of matter that lacks either a defined shape or a define volume. In other words, it fills a container and takes its shape. Any form of matter that exists as a solid or liquid also takes the form of a gas. Matter changes into a gas when temperature increases and pressure decreases.

Explanation: Pls mark me as brainiest

Aleksandr [31]3 years ago
5 0
The commercial sector uses natural gas to heat buildings and water, to operate refrigeration and cooling equipment, to cook, to dry clothes, and to provide outdoor lighting. Some consumers in the commercial sector also use natural gas as a fuel in combined heat and power systems.
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I need a answer ASAP
svet-max [94.6K]

Answer:

<h3>3.2 millions years old</h3>

Explanation:

i hope it helps :)

4 0
3 years ago
An aqueous solution of hydrobromic acid is standardized by titration with a 0.164 M solution of calcium hydroxide. If 14.9 mL of
Arada [10]

Answer:

The molarity of hydrobromic acid is 0.182 M

Explanation:

Step 1: Data given

Molarity of Calcium hydroxide = 0.164 M

Volume of calcium hydroxide = 14.9 mL = 0.0149 L

Volume  of HBr = 26.9 mL = 0.0269 L

Step 2: The balanced equation

Ca(OH)2 + 2HBr →CaBr2 + 2H2O

Step 3: Calculate molarity of HBr

b*Ca*Va = a*Cb*Vb

⇒b = the coefficient of HBr = 2

⇒Ca = the molarity of Ca(OH)2 = 0.164 M

⇒Va = the volume of ca(OH)2 = 0.0149 L

⇒a= the coefficient of Ca(OH)2 = 1

⇒Cb = the molarity of HBr = TO BE DETERMINED

⇒Vb = the volume of HBr = 0.0269 L

2*0.164 * 0.0149 = 1*Cb*0.0269

Cb = 0.182 M

The molarity of hydrobromic acid is 0.182 M

6 0
4 years ago
Balancing equations<br> C2H5OH + O2 —&gt; CO2 + H2O
Aneli [31]

Answer:

2 C2H5OH+ 21 o2 —> 4 CO2+ 6 H2o6

7 0
3 years ago
A sample of gas occupies 6. 8 L at 327 c what will be it volume at 27 c if the pressure and number of particles do not change
Vitek1552 [10]

A sample of gas occupies 6. 8 L at 327 c and the volume at 27 c if the pressure and number of particles do not change is 3.401 L.

<h3>What is volume?</h3>

Volume is a measurement of the three-dimensional space that is occupied. Numerous imperial units or the SI-derived units, such as the cubic meter and liter, are frequently used to quantify it numerically (such as the gallon, quart, cubic inch). Volume and the length (cubed) have a symbiotic relationship. The volume of a container is typically thought of as its capacity, not as the amount of the space it takes up. In the other words, the volume is the amount of fluid (liquid or gas) that the container may hold.

Volume was initially measured using naturally occurring vessels of a comparable shape and then with standardized containers. Arithmetic formulas can be used to quickly calculate the volume of the several straightforward three-dimensional shapes. If a formula for shape's boundary is known, it is possible to use integral calculus to determine the volumes of more complex shapes. No object in dimensions of zero, one, or two has volume; in the dimensions of four and above, the hypervolume is a concept similar to the standard volume.

In solving the any gas law problems, kelvin temperature will be used.

kelvin = degree celsius + 273.15

Kelvin = 327 + 273.15

                  = 600.15 K

Kelvin = 27 + 273.15

                  =  300.15 K

Given Data;

V_{1}(the initial volume) = 6.8 L                V_{2} (the final volume) = ? unknown

T_{1}(the initial temperature = 327 °C      T_{2}(the final temperature) = 27 °C

                                   =( 600.15 K)                                      = (300.15 K)

This problem can be solve using the Charles' Law which states that volume is directly proportional to kelvin temperature of gases if amount of gas and pressure are constant. If the temperature decreases, volume decreases.

Formula of the Charles' Law is \frac{V_{1} }{T_{1} }= \frac{V_{2} }{T_{2} }

To solve for V2, we can used formula V_{2} =\frac{V_{1}T_{2}  }{T_{1} }

V_{2} =\frac{V_{1}T_{2}  }{T_{1} }

    = 6.8 L × 300.15 K / 600.15 K       (cancel the unit kelvin)

    = 2041.02 L / 600.15

V_{2}= 3.401 L

Therefore, volume is 3.401 L

To know more about volume visit: brainly.com/question/1578538

#SPJ4

5 0
1 year ago
Please help me with this question
vlada-n [284]
The answer to that question is B
7 0
3 years ago
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