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2 years ago

3. Why does it tako 3 copies of; to show the same amount as 1 copy of ?? Explain your answer in words

1 answer:

7 0

Because 3/6 is equal to 1/2.
You multiply the 1 (in 1/2) by 3, and the 2 (in 1/2) by 3 to get 3/6. You need to have a common denominator, and 6 was the common denominator.

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Please help me with this problem

eimsori [14]

Find the equation of the first line using the two given points: (1,-1) (-1,-5)

Slope = change in Y over change in x:

Slope = (-5-(-1)) / (-1-(1) = -4/-2 = 2

Now find y intercept: y - y1 = m(x-x1) = y -(-1) = 2(x-1)

Simplify to get y = 2x-3

Now a perpendicular line has a opposite reciprocal slope.

The perpendicular line would be y = -1/2x - 3

You are told the y intercept is -4 units greater, so add -4 to -3 to get -7

The answer would be A. y = -1/2x-7

6 0

3 years ago

ILL GIVE YOU BRAINLIEST PLEASE HELP 20 POINTS

alisha [4.7K]

B. $27,000

I hope helped ^-^

7 0

3 years ago

Read 2 more answers

PLEASE HELP ASAP! The quotient of two rational numbers is positive. What can you conclude about the signs of the dividend and th

Anon25 [30]

Answer:

They either both have to be positive or negative.

Step-by-step explanation:

1 / 1 = 1

-1 / -1 = 1

This gets you positive, when both dividend and divisors are positive or negative.

-1 / 1 = -1

1 / -1 = -1

This gets you negative, when both dividend and divisors are different signs.

3 0

3 years ago

Read 2 more answers

Write 3x 1/2 in radical form

stiv31 [10]

Answer:

3x^1/2 in radical form is

$\sqrt{3x}$

Hope this helps you

8 0

3 years ago

Write the equation of a parabola having the vertex (1, −2) and containing the point (3, 6) in vertex form. Then, rewrite the equ

In-s [12.5K]

PART A

The equation of the parabola in vertex form is given by the formula,

$y - k = a {(x - h)}^{2}$

where

$(h,k)=(1,-2)$

is the vertex of the parabola.

We substitute these values to obtain,

$y + 2 = a {(x - 1)}^{2}$

The point, (3,6) lies on the parabola.

It must therefore satisfy its equation.

$6 + 2 = a {(3 - 1)}^{2}$

$8= a {(2)}^{2}$

$8=4a$

$a = 2$
Hence the equation of the parabola in vertex form is

$y + 2 = 2 {(x - 1)}^{2}$

PART B

To obtain the equation of the parabola in standard form, we expand the vertex form of the equation.

$y + 2 = 2{(x - 1)}^{2}$

This implies that

$y + 2 = 2(x - 1)(x - 1)$

We expand to obtain,

$y + 2 = 2( {x}^{2} - 2x + 1)$

This will give us,

$y + 2 = 2 {x}^{2} - 4x + 2$

$y = {x}^{2} - 4x$

This equation is now in the form,

$y = a {x}^{2} + bx + c$
where

$a=1,b=-4,c=0$

This is the standard form

7 0

3 years ago